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Give the exponential seq of 1/8, m, n, 1/512. Find m, n.

Mathematics

ScanSolve AI Answer

Answer

m=132,n=1128m = \frac{1}{32}, n = \frac{1}{128}

Step-by-step solution

4 steps

The given sequence is a Geometric Progression (GP): 18,m,n,1512\frac{1}{8}, m, n, \frac{1}{512}.
Let the first term be aa and the common ratio be rr.
The terms of a GP are a,ar,ar2,ar3,…a, ar, ar^2, ar^3, \dots

  1. Identify the first term and the fourth term.

    The first term is a=18a = \frac{1}{8}.
    The fourth term is ar3=1512ar^3 = \frac{1}{512}.

  2. Find the common ratio (rr).

    Substitute the value of aa into the equation for the fourth term:

    18r3=1512\frac{1}{8} r^3 = \frac{1}{512}

    Multiply both sides by 8:

    r3=8512r^3 = \frac{8}{512}

    Simplify the fraction:

    r3=164r^3 = \frac{1}{64}

    Take the cube root of both sides:

    r=1643r = \sqrt[3]{\frac{1}{64}} r=14r = \frac{1}{4}
  3. Find the value of mm.

    The second term is m=arm = ar.

    m=18×14m = \frac{1}{8} \times \frac{1}{4} m=132m = \frac{1}{32}
  4. Find the value of nn.

    The third term is n=ar2n = ar^2.

    n=18×(14)2n = \frac{1}{8} \times \left(\frac{1}{4}\right)^2 n=18×116n = \frac{1}{8} \times \frac{1}{16} n=1128n = \frac{1}{128}

    The values are m=132,n=1128m = \frac{1}{32}, n = \frac{1}{128}.

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