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Factorize 16-x4

Mathematics

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Answer

(2−x)(2+x)(4+x2)(2 - x)(2 + x)(4 + x^2)

Step-by-step solution

4 steps

यहाँ दिइएको अभिव्यक्तिलाई गुणनखण्ड गर्नुपर्नेछ:

16−x416 - x^4
  1. दिएको अभिव्यक्तिलाई वर्गहरूको भिन्नताको रूपमा लेख्नुहोस्।

    हामीलाई थाहा छ कि a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).
    यहाँ, 16=4216 = 4^2 र x4=(x2)2x^4 = (x^2)^2 हो।
    त्यसैले,

    16−x4=42−(x2)216 - x^4 = 4^2 - (x^2)^2
  2. वर्गहरूको भिन्नताको सूत्र प्रयोग गर्नुहोस्।

    42−(x2)2=(4−x2)(4+x2)4^2 - (x^2)^2 = (4 - x^2)(4 + x^2)
  3. पहिलो गुणनखण्ड (4−x2)(4 - x^2) लाई थप गुणनखण्ड गर्नुहोस्।

    यो पनि वर्गहरूको भिन्नता हो, जहाँ 4=224 = 2^2 र x2=x2x^2 = x^2 हो।

    4−x2=22−x2=(2−x)(2+x)4 - x^2 = 2^2 - x^2 = (2 - x)(2 + x)
  4. सबै गुणनखण्डहरूलाई एकसाथ लेख्नुहोस्।

    16−x4=(2−x)(2+x)(4+x2)16 - x^4 = (2 - x)(2 + x)(4 + x^2)

    अन्तिम उत्तर हो:

    (2−x)(2+x)(4+x2)(2 - x)(2 + x)(4 + x^2)
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