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Calculate the following 3. a. 37÷3=

Mathematics

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3 parts
a
111
b

19 remainder 319 \text{ remainder } 3

c

20 remainder 320 \text{ remainder } 3

Step-by-step solution

6 steps

Here are the calculations for the problems:

Part a· 2 steps

Calculate 37×337 \times 3

  1. Multiply the ones digit.

    7×3=217 \times 3 = 21

    Write down 1 and carry over 2.

  2. Multiply the tens digit and add the carried over value.

    3×3=93 \times 3 = 9 9+2=119 + 2 = 11

    Combine the results.

    37×3=11137 \times 3 = \boxed{111}

Part b

19 remainder 319 \text{ remainder } 3

Calculate 98÷598 \div 5

  1. Divide the tens digit.

    9÷5=1 with a remainder of 49 \div 5 = 1 \text{ with a remainder of } 4
  2. Combine the remainder with the ones digit to form 48.

    Divide 48 by 5.

    48÷5=9 with a remainder of 348 \div 5 = 9 \text{ with a remainder of } 3

    So, 98÷5=19 remainder 398 \div 5 = \boxed{19 \text{ remainder } 3}

Part c

20 remainder 320 \text{ remainder } 3

Calculate 83÷483 \div 4

  1. Divide the tens digit.

    8÷4=2 with a remainder of 08 \div 4 = 2 \text{ with a remainder of } 0
  2. Bring down the ones digit, 3.

    Divide 3 by 4.

    3÷4=0 with a remainder of 33 \div 4 = 0 \text{ with a remainder of } 3

    So, 83÷4=20 remainder 383 \div 4 = \boxed{20 \text{ remainder } 3}

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