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Solve the following addition problems with mixed numbers: a) 2 rac12 + 3 rac34 b) 1 rac38 + 9 rac13

Mathematics

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Answers

2 parts
a

6146\frac{1}{4}

b

10172410\frac{17}{24}

Step-by-step solution

9 steps

Here are the solutions for the addition problems:

Part a· 5 steps

To add 212+3342\frac{1}{2} + 3\frac{3}{4}

  1. Add the whole numbers and the fractions separately.

    2+3=52 + 3 = 5 12+34\frac{1}{2} + \frac{3}{4}
  2. Find a common denominator for the fractions.

    The least common multiple of 2 and 4 is 4.

    12=1×22×2=24\frac{1}{2} = \frac{1 \times 2}{2 \times 2} = \frac{2}{4}
  3. Add the fractions.

    24+34=2+34=54\frac{2}{4} + \frac{3}{4} = \frac{2+3}{4} = \frac{5}{4}
  4. Convert the improper fraction to a mixed number.

    54=114\frac{5}{4} = 1\frac{1}{4}
  5. Add the sum of the whole numbers to the sum of the fractions.

    5+114=6145 + 1\frac{1}{4} = 6\frac{1}{4}

    The final answer is 614\boxed{6\frac{1}{4}}.

Part b

10172410\frac{17}{24}

To add 138+9131\frac{3}{8} + 9\frac{1}{3}

  1. Add the whole numbers and the fractions separately.

    1+9=101 + 9 = 10 38+13\frac{3}{8} + \frac{1}{3}
  2. Find a common denominator for the fractions.

    The least common multiple of 8 and 3 is 24.

    38=3×38×3=924\frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24} 13=1×83×8=824\frac{1}{3} = \frac{1 \times 8}{3 \times 8} = \frac{8}{24}
  3. Add the fractions.

    924+824=9+824=1724\frac{9}{24} + \frac{8}{24} = \frac{9+8}{24} = \frac{17}{24}
  4. Combine the sum of the whole numbers with the sum of the fractions.

    10+1724=10172410 + \frac{17}{24} = 10\frac{17}{24}

    The final answer is 101724\boxed{10\frac{17}{24}}.

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