Solve the following algebraic equations and number patterns: 1) (2 + x) * 4 = 48, 2) (x - 12) / 3 = 6, 3) x - (12 / 3) = 6, 5) x − 3 + 5 = 12, 7) (16 − x) + 3 = 4. Also find the next three terms in th

Let the missing number be $x$.

Divide both sides by 4:

Subtract 2 from both sides:

The missing number is $\boxed{10}$.

Let the missing number be $x$.

Multiply both sides by 3:

Add 12 to both sides:

The missing number is $\boxed{30}$.

Let the missing number be $x$.

First, calculate the division in the parentheses:

Add 4 to both sides:

The missing number is $\boxed{10}$.

Let the missing number be $x$.

Combine the constant terms:

Subtract 2 from both sides:

The missing number is $\boxed{10}$.

Let the missing number be $x$.

Subtract 3 from both sides:

Subtract 16 from both sides:

Multiply both sides by -1:

The missing number is $\boxed{15}$.

The pattern is $1, 4, 7, 10, \dots$
This is an arithmetic sequence where each term is 3 more than the previous term. The common difference is 3.
The next three terms are:
$10 + 3 = 13$
$13 + 3 = 16$
$16 + 3 = 19$
The completed pattern is $\boxed{1, 4, 7, 10, 13, 16, 19}$.