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Solve the following decimal operations: a) 23.4 + 17.56, b) 45.7 - 18.92, c) 6.25 x 4. Then solve: a) 12.6 / 3, b) 45.5 / 5. Finally, convert decimals to fractions: a) 0.25, b) 0.6, c) 1.75.

Mathematics

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Here are the solutions to the questions:

Question 3

a)

  1. Add the decimals.

    23.4+17.56=40.9623.4 + 17.56 = 40.96

    The sum is 40.96\boxed{\text{40.96}}.

    b)

  2. Subtract the decimals.

    45.7−18.92=26.7845.7 - 18.92 = 26.78

    The difference is 26.78\boxed{\text{26.78}}.

    c)

  3. Multiply the numbers.

    6.25×4=25.006.25 \times 4 = 25.00

    The product is 25\boxed{\text{25}}.

    Question 4

    a)

  4. Divide the decimal by 3.

    12.6÷3=4.212.6 \div 3 = 4.2

    The quotient is 4.2\boxed{\text{4.2}}.

    b)

  5. Divide the decimal by 5.

    45.5÷5=9.145.5 \div 5 = 9.1

    The quotient is 9.1\boxed{\text{9.1}}.

    Question 5

    a)

  6. Write the decimal as a fraction.

    0.25=251000.25 = \frac{25}{100}
  7. Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 25.

    25100=25÷25100÷25=14\frac{25}{100} = \frac{25 \div 25}{100 \div 25} = \frac{1}{4}

    The fraction is 14\boxed{\frac{1}{4}}.

    b)

  8. Write the decimal as a fraction.

    0.6=6100.6 = \frac{6}{10}
  9. Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 2.

    610=6÷210÷2=35\frac{6}{10} = \frac{6 \div 2}{10 \div 2} = \frac{3}{5}

    The fraction is 35\boxed{\frac{3}{5}}.

    c)

  10. Write the decimal as a mixed number or improper fraction.

    1.75=1751001.75 = 1\frac{75}{100}
  11. Simplify the fractional part 75100\frac{75}{100} by dividing the numerator and denominator by their greatest common divisor, which is 25.

    75100=75÷25100÷25=34\frac{75}{100} = \frac{75 \div 25}{100 \div 25} = \frac{3}{4}
  12. Combine the whole number and the simplified fraction.

    134=1×4+34=741\frac{3}{4} = \frac{1 \times 4 + 3}{4} = \frac{7}{4}

    The fraction is 74\boxed{\frac{7}{4}}.

    Question 6

    a)

  13. Multiply the cost of one packet by the number of packets.

    Cost of 4 packets=R12.50×4=R50.00\text{Cost of 4 packets} = \text{R}12.50 \times 4 = \text{R}50.00

    The cost of 4 packets is R50.00\boxed{\text{R}50.00}.

    b)

  14. Subtract the total cost from the amount paid.

    Change received=R100.00−R50.00=R50.00\text{Change received} = \text{R}100.00 - \text{R}50.00 = \text{R}50.00

    The change received will be R50.00\boxed{\text{R}50.00}.

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