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Evaluate the following limits: 5. x 0^+ |x|, x 0^- |x| 6. x 2^+ |x - 2|, x 2^- |x - 2| 7. _x 0^+ (|x|)/(x)

Mathematics

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5. Evaluate:

  • Part 1: lim⁡x→0+∣x∣\lim_{x \to 0^+} |x|
  1. For x>0x > 0, the absolute value ∣x∣|x| is equal to xx.

    $$
    \lim_{x \to 0^+} |x| = \lim_{x \to 0^+} x
    $$
    
  2. Substitute x=0x=0 into the expression.

    $$
    \lim_{x \to 0^+} x = 0
    $$
    The limit is $\boxed{\text{0}}$.
    
    • Part 2: lim⁡x→0−∣x∣\lim_{x \to 0^-} |x|
  3. For x<0x < 0, the absolute value ∣x∣|x| is equal to −x-x.

    $$
    \lim_{x \to 0^-} |x| = \lim_{x \to 0^-} (-x)
    $$
    
  4. Substitute x=0x=0 into the expression.

    $$
    \lim_{x \to 0^-} (-x) = -(0) = 0
    $$
    The limit is $\boxed{\text{0}}$.
    

    6. Evaluate:

    • Part 1: lim⁡x→2+∣x−2∣\lim_{x \to 2^+} |x - 2|
  5. For x>2x > 2, the expression x−2x - 2 is positive, so ∣x−2∣=x−2|x - 2| = x - 2.

    $$
    \lim_{x \to 2^+} |x - 2| = \lim_{x \to 2^+} (x - 2)
    $$
    
  6. Substitute x=2x=2 into the expression.

    $$
    \lim_{x \to 2^+} (x - 2) = 2 - 2 = 0
    $$
    The limit is $\boxed{\text{0}}$.
    
    • Part 2: lim⁡x→2−∣x−2∣\lim_{x \to 2^-} |x - 2|
  7. For x<2x < 2, the expression x−2x - 2 is negative, so ∣x−2∣=−(x−2)|x - 2| = -(x - 2).

    $$
    \lim_{x \to 2^-} |x - 2| = \lim_{x \to 2^-} -(x - 2)
    $$
    
  8. Substitute x=2x=2 into the expression.

    $$
    \lim_{x \to 2^-} -(x - 2) = -(2 - 2) = -(0) = 0
    $$
    The limit is $\boxed{\text{0}}$.
    

    7. Evaluate:

    • Part 1: lim⁡x→0+∣x∣x\lim_{x \to 0^+} \frac{|x|}{x}
  9. For x>0x > 0, the absolute value ∣x∣|x| is equal to xx.

    $$
    \lim_{x \to 0^+} \frac{|x|}{x} = \lim_{x \to 0^+} \frac{x}{x}
    $$
    
  10. Simplify the expression.

    $$
    \lim_{x \to 0^+} \frac{x}{x} = \lim_{x \to 0^+} 1
    $$
    
  11. The limit of a constant is the constant itself.

    $$
    \lim_{x \to 0^+} 1 = 1
    $$
    The limit is $\boxed{\text{1}}$.
    
    • Part 2: lim⁡x→0−∣x∣x\lim_{x \to 0^-} \frac{|x|}{x}
  12. For x<0x < 0, the absolute value ∣x∣|x| is equal to −x-x.

    $$
    \lim_{x \to 0^-} \frac{|x|}{x} = \lim_{x \to 0^-} \frac{-x}{x}
    $$
    
  13. Simplify the expression.

    $$
    \lim_{x \to 0^-} \frac{-x}{x} = \lim_{x \to 0^-} (-1)
    $$
    
  14. The limit of a constant is the constant itself.

    $$
    \lim_{x \to 0^-} (-1) = -1
    $$
    The limit is $\boxed{\text{-1}}$.
    
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