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Solve the following linear inequalities.

Mathematics

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Step-by-step solution

15 steps

Here are the solutions to the inequalities:

1. 4x+2>−64x + 2 > -6

  1. Subtract 2 from both sides of the inequality.

    4x+2−2>−6−24x + 2 - 2 > -6 - 2 4x>−84x > -8
  2. Divide both sides by 4.

    4x4>−84\frac{4x}{4} > \frac{-8}{4} x>−2x > -2

    The solution is x>−2\boxed{x > -2}.

    2. 1−2x≤−51 - 2x \le -5

  3. Subtract 1 from both sides of the inequality.

    1−2x−1≤−5−11 - 2x - 1 \le -5 - 1 −2x≤−6-2x \le -6
  4. Divide both sides by -2.

    Remember to reverse the inequality sign when dividing by a negative number.

    −2x−2≥−6−2\frac{-2x}{-2} \ge \frac{-6}{-2} x≥3x \ge 3

    The solution is x≥3\boxed{x \ge 3}.

    3. 3x+24≤2\frac{3x+2}{4} \le 2

  5. Multiply both sides by 4.

    3x+24×4≤2×4\frac{3x+2}{4} \times 4 \le 2 \times 4 3x+2≤83x + 2 \le 8
  6. Subtract 2 from both sides.

    3x+2−2≤8−23x + 2 - 2 \le 8 - 2 3x≤63x \le 6
  7. Divide both sides by 3.

    3x3≤63\frac{3x}{3} \le \frac{6}{3} x≤2x \le 2

    The solution is x≤2\boxed{x \le 2}.

    4. 3−2x2>−3\frac{3-2x}{2} > -3

  8. Multiply both sides by 2.

    3−2x2×2>−3×2\frac{3-2x}{2} \times 2 > -3 \times 2 3−2x>−63 - 2x > -6
  9. Subtract 3 from both sides.

    3−2x−3>−6−33 - 2x - 3 > -6 - 3 −2x>−9-2x > -9
  10. Divide both sides by -2.

    Remember to reverse the inequality sign.

    −2x−2<−9−2\frac{-2x}{-2} < \frac{-9}{-2} x<92x < \frac{9}{2}

    The solution is x<92\boxed{x < \frac{9}{2}}.

    5. 12(x+4)<3\frac{1}{2}(x+4) < 3

  11. Multiply both sides by 2.

    12(x+4)×2<3×2\frac{1}{2}(x+4) \times 2 < 3 \times 2 x+4<6x + 4 < 6
  12. Subtract 4 from both sides.

    x+4−4<6−4x + 4 - 4 < 6 - 4 x<2x < 2

    The solution is x<2\boxed{x < 2}.

    6. 3(1−2x)≥53(1-2x) \ge 5

  13. Distribute the 3 on the left side.

    3×1−3×2x≥53 \times 1 - 3 \times 2x \ge 5 3−6x≥53 - 6x \ge 5
  14. Subtract 3 from both sides.

    3−6x−3≥5−33 - 6x - 3 \ge 5 - 3 −6x≥2-6x \ge 2
  15. Divide both sides by -6.

    Remember to reverse the inequality sign.

    −6x−6≤2−6\frac{-6x}{-6} \le \frac{2}{-6} x≤−13x \le -\frac{1}{3}

    The solution is x≤−13\boxed{x \le -\frac{1}{3}}.

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