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Write the following numbers as powers: a) 9 b) 25 c) 49 d) 27 e) 121 f) 125

Mathematics

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Answers

6 parts
a

323^2

b

525^2

c

727^2

d

333^3

e

11211^2

f

535^3

Step-by-step solution

12 steps

Hier is die oplossing vir .1:

Part a· 2 steps

9

  1. Vind 'n getal wat met homself vermenigvuldig word om 9 te kry.

    3×3=93 \times 3 = 9
  2. Skryf dit as 'n mag.

    9=329 = 3^2

    Die antwoord is 32\boxed{3^2}.

Part b

525^2

25

  1. Vind 'n getal wat met homself vermenigvuldig word om 25 te kry.

    5×5=255 \times 5 = 25
  2. Skryf dit as 'n mag.

    25=5225 = 5^2

    Die antwoord is 52\boxed{5^2}.

Part c

727^2

49

  1. Vind 'n getal wat met homself vermenigvuldig word om 49 te kry.

    7×7=497 \times 7 = 49
  2. Skryf dit as 'n mag.

    49=7249 = 7^2

    Die antwoord is 72\boxed{7^2}.

Part d

333^3

27

  1. Vind 'n getal wat met homself 'n sekere aantal kere vermenigvuldig word om 27 te kry.

    3×3×3=9×3=273 \times 3 \times 3 = 9 \times 3 = 27
  2. Skryf dit as 'n mag.

    27=3327 = 3^3

    Die antwoord is 33\boxed{3^3}.

Part e

11211^2

121

  1. Vind 'n getal wat met homself vermenigvuldig word om 121 te kry.

    11×11=12111 \times 11 = 121
  2. Skryf dit as 'n mag.

    121=112121 = 11^2

    Die antwoord is 112\boxed{11^2}.

Part f

535^3

125

  1. Vind 'n getal wat met homself 'n sekere aantal kere vermenigvuldig word om 125 te kry.

    5×5×5=25×5=1255 \times 5 \times 5 = 25 \times 5 = 125
  2. Skryf dit as 'n mag.

    125=53125 = 5^3

    Die antwoord is 53\boxed{5^3}.

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