Write the following prime factors b.96

Start by dividing 96 by the smallest prime number, 2.
$96 \div 2 = 48$

Continue dividing the result by 2 until it's no longer divisible by 2.
$48 \div 2 = 24$
$24 \div 2 = 12$
$12 \div 2 = 6$
$6 \div 2 = 3$

The current result is 3, which is a prime number.
$3 \div 3 = 1$

The prime factors are all the divisors used: 2, 2, 2, 2, 2, and 3.
So, $96 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 = 2^5 \times 3$.

The prime factors of 96 are:
2^5 \times 3