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Solve the following problems: 1. Inequalities: i) 4(2x+3) < 7−2x ii) 3x+2 > 2x+5. 2. Venn Diagram (Set Theory) with given values.

Mathematics

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Answers

4 parts
i

x<−12x < -\frac{1}{2}

ii

x>3x > 3

b(ii)
6

\28.57$

\71.43$

Step-by-step solution

11 steps

Here are the solutions to the problems:

1. Inequalities

Part i· 4 steps

Solve 4(2x+3)<7−2x4(2x+3) < 7-2x.

  1. Distribute the 4 on the left side.

    8x+12<7−2x8x + 12 < 7 - 2x
  2. Add $2x$ to both sides.

    10x+12<710x + 12 < 7
  3. Subtract 12 from both sides.

    10x<7−1210x < 7 - 12 10x<−510x < -5
  4. Divide by 10.

    x<−510x < -\frac{5}{10} x<−12x < -\frac{1}{2}

    The solution is x<−12\boxed{x < -\frac{1}{2}}.

Part ii

x>3x > 3

Solve 3x+2>2x+53x+2 > 2x+5.

  1. Subtract $2x$ from both sides.

    3x−2x+2>53x - 2x + 2 > 5 x+2>5x + 2 > 5
  2. Subtract 2 from both sides.

    x>5−2x > 5 - 2 x>3x > 3

    The solution is x>3\boxed{x > 3}.

    2. Venn Diagram (Set Theory)

    Let G be the set of people who watched GTV, K for KTV, and M for MTV.
    Given:
    Total people = 70
    ∣G∣=32|G| = 32
    ∣K∣=24|K| = 24
    ∣M∣=22|M| = 22
    ∣G∩K∣=14|G \cap K| = 14
    ∣K∩M∣=8|K \cap M| = 8
    ∣G∩M∣=13|G \cap M| = 13
    ∣G∩K∩M∣=5|G \cap K \cap M| = 5

Part a

Illustrate the information in a Venn diagram.

First, calculate the "only" regions:
∣G∩K only∣=∣G∩K∣−∣G∩K∩M∣=14−5=9|G \cap K \text{ only}| = |G \cap K| - |G \cap K \cap M| = 14 - 5 = 9
∣K∩M only∣=∣K∩M∣−∣G∩K∩M∣=8−5=3|K \cap M \text{ only}| = |K \cap M| - |G \cap K \cap M| = 8 - 5 = 3
∣G∩M only∣=∣G∩M∣−∣G∩K∩M∣=13−5=8|G \cap M \text{ only}| = |G \cap M| - |G \cap K \cap M| = 13 - 5 = 8

Next, calculate the number of people who watched only one channel:
∣G only∣=∣G∣−(∣G∩K only∣+∣G∩M only∣+∣G∩K∩M∣)=32−(9+8+5)=32−22=10|G \text{ only}| = |G| - (|G \cap K \text{ only}| + |G \cap M \text{ only}| + |G \cap K \cap M|) = 32 - (9 + 8 + 5) = 32 - 22 = 10
∣K only∣=∣K∣−(∣G∩K only∣+∣K∩M only∣+∣G∩K∩M∣)=24−(9+3+5)=24−17=7|K \text{ only}| = |K| - (|G \cap K \text{ only}| + |K \cap M \text{ only}| + |G \cap K \cap M|) = 24 - (9 + 3 + 5) = 24 - 17 = 7
∣M only∣=∣M∣−(∣K∩M only∣+∣G∩M only∣+∣G∩K∩M∣)=22−(3+8+5)=22−16=6|M \text{ only}| = |M| - (|K \cap M \text{ only}| + |G \cap M \text{ only}| + |G \cap K \cap M|) = 22 - (3 + 8 + 5) = 22 - 16 = 6

The Venn diagram would show three overlapping circles for G, K, and M.

  • The center intersection (G ∩\cap K ∩\cap M) would be 5.
  • The intersection of G and K only would be 9.
  • The intersection of K and M only would be 3.
  • The intersection of G and M only would be 8.
  • The G only region would be 10.
  • The K only region would be 7.
  • The M only region would be 6.

Part b(i)22

did not watch TV at all

Find the number of people who

  1. Calculate the total number of people who watched at least one channel.

    ∣G∪K∪M∣=∣G only∣+∣K only∣+∣M only∣+∣G∩K only∣+∣K∩M only∣+∣G∩M only∣+∣G∩K∩M∣|G \cup K \cup M| = |G \text{ only}| + |K \text{ only}| + |M \text{ only}| + |G \cap K \text{ only}| + |K \cap M \text{ only}| + |G \cap M \text{ only}| + |G \cap K \cap M| ∣G∪K∪M∣=10+7+6+9+3+8+5=48|G \cup K \cup M| = 10 + 7 + 6 + 9 + 3 + 8 + 5 = 48
  2. Subtract this from the total number of people interviewed.

    Did not watch TV=Total people−∣G∪K∪M∣\text{Did not watch TV} = \text{Total people} - |G \cup K \cup M| Did not watch TV=70−48=22\text{Did not watch TV} = 70 - 48 = 22

    The number of people who did not watch TV at all is 22\boxed{22}.

Part b(ii)6

watched MTV only

From the calculations above, the number of people who watched MTV only is 6\boxed{6}.

3. Ratio and Proportion

Lois and Gina share $100.00 in the ratio 2:5.

  1. Find the total number of parts in the ratio.

    Total parts=2+5=7\text{Total parts} = 2 + 5 = 7
  2. Calculate Lois's share.

    Lois’s share=27×$100.00=$200.007≈$28.57\text{Lois's share} = \frac{2}{7} \times \$100.00 = \frac{\$200.00}{7} \approx \$28.57

  3. Calculate Gina's share.

    Gina’s share=57×$100.00=$500.007≈$71.43\text{Gina's share} = \frac{5}{7} \times \$100.00 = \frac{\$500.00}{7} \approx \$71.43 Lois receives \boxed{\28.57}andGinareceivesand Gina receives\boxed{$71.43}$.

    4. Table Completion (Function Evaluation)

    Complete the table for the relation y=5+3x−x2y = 5 + 3x - x^2 from x=−2x = -2 to x=5x = 5.

    xxy=5+3x−x2y = 5 + 3x - x^2
    -25+3(−2)−(−2)2=5−6−4=−55 + 3(-2) - (-2)^2 = 5 - 6 - 4 = -5
    -15+3(−1)−(−1)2=5−3−1=15 + 3(-1) - (-1)^2 = 5 - 3 - 1 = 1
    05+3(0)−(0)2=5+0−0=55 + 3(0) - (0)^2 = 5 + 0 - 0 = 5
    15+3(1)−(1)2=5+3−1=75 + 3(1) - (1)^2 = 5 + 3 - 1 = 7
    25+3(2)−(2)2=5+6−4=75 + 3(2) - (2)^2 = 5 + 6 - 4 = 7
    35+3(3)−(3)2=5+9−9=55 + 3(3) - (3)^2 = 5 + 9 - 9 = 5
    45+3(4)−(4)2=5+12−16=15 + 3(4) - (4)^2 = 5 + 12 - 16 = 1
    55+3(5)−(5)2=5+15−25=−55 + 3(5) - (5)^2 = 5 + 15 - 25 = -5

    The completed table is:

    x−2−1012345y-5157751-5\begin{array}{|c|c|c|c|c|c|c|c|c|} \hline x & -2 & -1 & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline y & \textbf{-5} & \textbf{1} & \textbf{5} & \textbf{7} & \textbf{7} & \textbf{5} & \textbf{1} & \textbf{-5} \\ \hline \end{array}

    Last free one today — make it count tomorrow,

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