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Solve the following problems: a) Calculate the future value of an investment... b) If 12 men working 8 hours a day can finish a job in 15 days, how many hours a day must 20 men work to finish the job

Mathematics

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Question 1a:

  1. Identify the given values.

    Principal amount, P=4000 FP = 4000 \text{ F}
    Annual interest rate, r=6%=0.06r = 6\% = 0.06
    Compounded quarterly, so n=4n = 4
    Time, t=5 yearst = 5 \text{ years}

  2. Use the compound interest formula A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}.

    A=4000(1+0.064)4×5A = 4000\left(1 + \frac{0.06}{4}\right)^{4 \times 5} A=4000(1+0.015)20A = 4000(1 + 0.015)^{20} A=4000(1.015)20A = 4000(1.015)^{20} A=4000×1.346855A = 4000 \times 1.346855 A=5387.42 FA = 5387.42 \text{ F}

    The amount of money in the account after 5 years will be 5387.42 F\boxed{\text{5387.42 F}}.

    Question 1b:

  3. Calculate the total man-hours required for the work.

    Total man-hours = Number of men ×\times Hours per day ×\times Number of days

    Total man-hours=12 men×8 hours/day×15 days=1440 man-hours\text{Total man-hours} = 12 \text{ men} \times 8 \text{ hours/day} \times 15 \text{ days} = 1440 \text{ man-hours}
  4. Calculate the hours per day required for 20 men to finish the work in 8 days.

    Let HH be the hours per day.

    20 men×H hours/day×8 days=1440 man-hours20 \text{ men} \times H \text{ hours/day} \times 8 \text{ days} = 1440 \text{ man-hours} 160H=1440160 H = 1440 H=1440160H = \frac{1440}{160} H=9 hours/dayH = 9 \text{ hours/day}

    20 men must work 9 hours per day\boxed{\text{9 hours per day}}.

    Question 1c:

  5. Identify the given information.

    Tickets sold = 480,000
    This represents 80% of all available tickets.

  6. Set up an equation to find the total number of available tickets.

    Let TT be the total number of available tickets.

    0.80×T=480,0000.80 \times T = 480,000
  7. Solve for TT.

    T=480,0000.80T = \frac{480,000}{0.80} T=600,000T = 600,000

    The total number of tickets that were available for the tournament is 600,000\boxed{\text{600,000}}.

    Question 2i:
    To represent the information on a Venn diagram, we first calculate the number of people in each distinct region.
    Total people = 50
    Let P = Politics, A = Advertisement, S = Sports.

    Given:
    ∣P∣=25|P| = 25
    ∣A∣=16|A| = 16
    ∣S∣=14|S| = 14
    ∣P∩A∣=5|P \cap A| = 5
    ∣A∩S∣=6|A \cap S| = 6
    ∣P∩S∣=4|P \cap S| = 4
    ∣P∩A∩S∣=2|P \cap A \cap S| = 2

  8. Find the number of people who read exactly two sections.

    • Only P and A: ∣P∩A∣−∣P∩A∩S∣=5−2=3|P \cap A| - |P \cap A \cap S| = 5 - 2 = 3
    • Only A and S: ∣A∩S∣−∣P∩A∩S∣=6−2=4|A \cap S| - |P \cap A \cap S| = 6 - 2 = 4
    • Only P and S: ∣P∩S∣−∣P∩A∩S∣=4−2=2|P \cap S| - |P \cap A \cap S| = 4 - 2 = 2
  9. Find the number of people who read exactly one section.

    • Only P: ∣P∣−(Only P and A+Only P and S+∣P∩A∩S∣)=25−(3+2+2)=25−7=18|P| - (\text{Only P and A} + \text{Only P and S} + |P \cap A \cap S|) = 25 - (3 + 2 + 2) = 25 - 7 = 18
    • Only A: ∣A∣−(Only P and A+Only A and S+∣P∩A∩S∣)=16−(3+4+2)=16−9=7|A| - (\text{Only P and A} + \text{Only A and S} + |P \cap A \cap S|) = 16 - (3 + 4 + 2) = 16 - 9 = 7
    • Only S: ∣S∣−(Only P and S+Only A and S+∣P∩A∩S∣)=14−(2+4+2)=14−8=6|S| - (\text{Only P and S} + \text{Only A and S} + |P \cap A \cap S|) = 14 - (2 + 4 + 2) = 14 - 8 = 6
  10. Find the number of people who read none of the sections.

    Total people in at least one section = (Only P) + (Only A) + (Only S) + (Only P and A) + (Only A and S) + (Only P and S) + (P∩A∩SP \cap A \cap S)

    =18+7+6+3+4+2+2=42= 18 + 7 + 6 + 3 + 4 + 2 + 2 = 42

    Number of people who read none = Total people - Total people in at least one section

    =50−42=8= 50 - 42 = 8

    The information for the Venn diagram is:

    • Only Politics: 18\boxed{\text{18}}
    • Only Advertisement: 7\boxed{\text{7}}
    • Only Sports: 6\boxed{\text{6}}
    • Only Politics and Advertisement: 3\boxed{\text{3}}
    • Only Advertisement and Sports: 4\boxed{\text{4}}
    • Only Politics and Sports: 2\boxed{\text{2}}
    • Politics, Advertisement, and Sports: 2\boxed{\text{2}}
    • None of the sections: 8\boxed{\text{8}}
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