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Solve the following quadratic equations using the factorization method: a) x2 + 8x + 12 = 0 b) x2 − 6x + 5 = 0

Mathematics

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Answers

2 parts
a

x=−6,x=−2x = -6, x = -2

b

x=1,x=5x = 1, x = 5

Step-by-step solution

10 steps

Here are the solutions using the factorization method:

Part a· 5 steps

x2+8x+12=0x^2 + 8x + 12 = 0

  1. Find two numbers that multiply to 12 (the constant term) and add up to 8 (the coefficient of the xx term).

    The numbers are 6 and 2.

  2. Rewrite the middle term using these two numbers.

    x2+6x+2x+12=0x^2 + 6x + 2x + 12 = 0
  3. Group the terms and factor out the common factors from each group.

    x(x+6)+2(x+6)=0x(x+6) + 2(x+6) = 0
  4. Factor out the common binomial factor (x+6)(x+6).

    (x+6)(x+2)=0(x+6)(x+2) = 0
  5. Set each factor equal to zero and solve for xx.

    x+6=0orx+2=0x+6 = 0 \quad \text{or} \quad x+2 = 0 x=−6orx=−2x = -6 \quad \text{or} \quad x = -2

    The solutions are x=−6,x=−2\boxed{x = -6, x = -2}.

Part b

x=1,x=5x = 1, x = 5

x2−6x+5=0x^2 - 6x + 5 = 0

  1. Find two numbers that multiply to 5 (the constant term) and add up to -6 (the coefficient of the xx term).

    The numbers are -1 and -5.

  2. Rewrite the middle term using these two numbers.

    x2−1x−5x+5=0x^2 - 1x - 5x + 5 = 0
  3. Group the terms and factor out the common factors from each group.

    x(x−1)−5(x−1)=0x(x-1) - 5(x-1) = 0
  4. Factor out the common binomial factor (x−1)(x-1).

    (x−1)(x−5)=0(x-1)(x-5) = 0
  5. Set each factor equal to zero and solve for xx.

    x−1=0orx−5=0x-1 = 0 \quad \text{or} \quad x-5 = 0 x=1orx=5x = 1 \quad \text{or} \quad x = 5

    The solutions are x=1,x=5\boxed{x = 1, x = 5}.

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