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Solve the following question: a) Convert 500 cm to m. b) If the perimeter and length of the rectangle are 20 cm and 6 cm respectively, calculate the breadth of the rectangle. c) Find the volume of the

Mathematics

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6. Solve the following question

a) Convert 500 cm to m.

  1. Recall the conversion factor between centimeters and meters.

    1 m=100 cm1 \text{ m} = 100 \text{ cm}
  2. Convert 500 cm to meters.

    500 cm=500100 m=5 m500 \text{ cm} = \frac{500}{100} \text{ m} = 5 \text{ m}

    The conversion is 5 m\boxed{\text{5 m}}.

    b) If the perimeter and length of the rectangle are 20 cm and 6 cm respectively, calculate the breadth of the rectangle.

  3. Write the formula for the perimeter of a rectangle.

    P=2(l+b)P = 2(l + b)

    where PP is the perimeter, ll is the length, and bb is the breadth.

  4. Substitute the given values (P=20 cmP = 20 \text{ cm}, l=6 cml = 6 \text{ cm}) into the formula.

    20=2(6+b)20 = 2(6 + b)
  5. Solve for bb.

    202=6+b\frac{20}{2} = 6 + b 10=6+b10 = 6 + b b=10−6b = 10 - 6 b=4 cmb = 4 \text{ cm}

    The breadth of the rectangle is 4 cm\boxed{\text{4 cm}}.

    c) Find the volume of the given cuboid.

  6. Identify the dimensions of the cuboid from the image.

    Length (ll) = 5 cm
    Width (ww) = 3 cm
    Height (hh) = 4 cm

  7. Write the formula for the volume of a cuboid.

    V=l×w×hV = l \times w \times h
  8. Substitute the dimensions and calculate the volume.

    V=5 cm×3 cm×4 cmV = 5 \text{ cm} \times 3 \text{ cm} \times 4 \text{ cm} V=15 cm2×4 cmV = 15 \text{ cm}^2 \times 4 \text{ cm} V=60 cm3V = 60 \text{ cm}^3

    The volume of the cuboid is 60 cm3\boxed{\text{60 cm}^3}.

    7. Solve the following question

    a) Write in indices: 32×6×33^2 \times 6 \times 3.

  9. Express all numbers as products of their prime factors.

    6=2×36 = 2 \times 3
  10. Substitute the prime factors back into the expression.

    32×(2×3)×33^2 \times (2 \times 3) \times 3
  11. Group terms with the same base and apply the exponent rule am×an=am+na^m \times a^n = a^{m+n}.

    2×32×31×312 \times 3^2 \times 3^1 \times 3^1 2×3(2+1+1)2 \times 3^{(2+1+1)} 2×342 \times 3^4

    The expression in indices is 2×34\boxed{2 \times 3^4}.

    b) Simplify: 8a+6b−4a8a + 6b - 4a.

  12. Identify and group like terms.

    (8a−4a)+6b(8a - 4a) + 6b
  13. Combine the like terms.

    4a+6b4a + 6b

    The simplified expression is 4a+6b\boxed{4a + 6b}.

    8. Solve the following question

    a) Multiply: 5x×x−5x5x \times x - 5x.

  14. Perform the multiplication first.

    5x×x=5x25x \times x = 5x^2
  15. Substitute the result back into the expression.

    5x2−5x5x^2 - 5x

    The multiplied expression is 5x2−5x\boxed{5x^2 - 5x}.

    b) Divide: 20x3÷4x2y20x^3 \div 4x^2y.

  16. Write the division as a fraction.

    20x34x2y\frac{20x^3}{4x^2y}
  17. Divide the coefficients and apply the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n} for variables.

    204×x3x2×1y\frac{20}{4} \times \frac{x^3}{x^2} \times \frac{1}{y} 5×x(3−2)×1y5 \times x^{(3-2)} \times \frac{1}{y} 5x×1y5x \times \frac{1}{y} 5xy\frac{5x}{y}

    The result of the division is 5xy\boxed{\frac{5x}{y}}.

    c) 1 is a prime number. Is this statement true, false or open?

  18. Recall the definition of a prime number.

    A prime number is a natural number greater than 1 that has exactly two distinct positive divisors: 1 and itself.

  19. Evaluate the number 1 against this definition.

    The number 1 is not greater than 1, and it only has one positive divisor (which is 1). Therefore, 1 does not fit the definition of a prime number.
    The statement "1 is a prime number" is False\boxed{\text{False}}.

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