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Write the following sentences as algebraic equations and solve for the variable: a) Half a number, x, plus 17 is equal to 97. b) Double a number, y, plus 4 is equal to -4. c) Four times a number, z, i

Mathematics

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Answers

4 parts
a

160\text{160}

b

-4\text{-4}

c

15\text{15}

d

10 or -10\text{10 or -10}

Step-by-step solution

10 steps

Part a· 3 steps

  1. Write the sentence as an algebraic equation.

    "Half a number, xx, plus 17 is equal to 97" translates to:

    x2+17=97\frac{x}{2} + 17 = 97
  2. Subtract 17 from both sides of the equation.

    x2+17−17=97−17\frac{x}{2} + 17 - 17 = 97 - 17 x2=80\frac{x}{2} = 80
  3. Multiply both sides by 2 to solve for xx.

    x2×2=80×2\frac{x}{2} \times 2 = 80 \times 2 x=160x = 160

    The value of xx is 160\boxed{\text{160}}.

Part b

-4\text{-4}

  1. Write the sentence as an algebraic equation.

    "Double a number, yy, plus 4 is equal to -4" translates to:

    2y+4=−42y + 4 = -4
  2. Subtract 4 from both sides of the equation.

    2y+4−4=−4−42y + 4 - 4 = -4 - 4 2y=−82y = -8
  3. Divide both sides by 2 to solve for yy.

    2y2=−82\frac{2y}{2} = \frac{-8}{2} y=−4y = -4

    The value of yy is -4\boxed{\text{-4}}.

Part c

15\text{15}

  1. Write the sentence as an algebraic equation.

    "Four times a number, zz, is one more than 59" translates to:

    4z=59+14z = 59 + 1 4z=604z = 60
  2. Divide both sides by 4 to solve for zz.

    4z4=604\frac{4z}{4} = \frac{60}{4} z=15z = 15

    The value of zz is 15\boxed{\text{15}}.

Part d

10 or -10\text{10 or -10}

  1. Write the sentence as an algebraic equation.

    "The square of an integer, pp, is 21 less than 121" translates to:

    p2=121−21p^2 = 121 - 21 p2=100p^2 = 100
  2. Take the square root of both sides to solve for pp.

    Remember that an integer can be positive or negative.

    p2=100\sqrt{p^2} = \sqrt{100} p=±10p = \pm 10

    The value of pp is 10 or -10\boxed{\text{10 or -10}}.

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