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Solve for the missing numbers in the given equations: Box + Box = 53, Box − Box = 2, where the numbers 11 and 25 are related to the first equation and 11 and 37 are related to the second.

Mathematics

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Answer

A=19.5,B=33.5,C=5.5,D=3.5A=19.5, B=33.5, C=5.5, D=3.5

Step-by-step solution

5 steps

Let the values in the boxes be represented by variables:

[ABCD]\begin{bmatrix} A & B \\ C & D \end{bmatrix}

From the image, we can form the following system of equations:

  1. Set up the equations based on the image.

    1. A+B=53A + B = 53
    2. A+C=25A + C = 25
    3. B+D=37B + D = 37
    4. C−D=2C - D = 2
  2. Solve for CC and DD in terms of AA and BB.

    From equation (2), C=25−AC = 25 - A.
    From equation (3), D=37−BD = 37 - B.

  3. Substitute these expressions for CC and DD into equation (4).

    (25−A)−(37−B)=2(25 - A) - (37 - B) = 2 25−A−37+B=225 - A - 37 + B = 2 B−A−12=2B - A - 12 = 2 B−A=14(Equation 5)B - A = 14 \quad (\text{Equation 5})
  4. Solve the system of equations (1) and (5) for AA and BB.

    We have:

    A+B=53(Equation 1)A + B = 53 \quad (\text{Equation 1}) −A+B=14(Equation 5)-A + B = 14 \quad (\text{Equation 5})

    Add Equation 1 and Equation 5:

    (A+B)+(−A+B)=53+14(A + B) + (-A + B) = 53 + 14 2B=672B = 67 B=672=33.5B = \frac{67}{2} = 33.5

    Substitute the value of BB into Equation 1:

    A+33.5=53A + 33.5 = 53 A=53−33.5A = 53 - 33.5 A=19.5A = 19.5
  5. Substitute the values of AA and BB back into the expressions for CC and DD.

    C=25−A=25−19.5=5.5C = 25 - A = 25 - 19.5 = 5.5 D=37−B=37−33.5=3.5D = 37 - B = 37 - 33.5 = 3.5

    The values in the boxes are:

    [19.533.55.53.5]\begin{bmatrix} 19.5 & 33.5 \\ 5.5 & 3.5 \end{bmatrix}

    The final answer is A=19.5,B=33.5,C=5.5,D=3.5A=19.5, B=33.5, C=5.5, D=3.5.

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