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For the quadratic equation 2x2 − 6x + 3a = 0, find the value of a that results in equal roots.

Mathematics

ScanSolve AI Answer

Answer

D

Step-by-step solution

3 steps

Here's the solution for question 34.

  1. Identify the condition for equal roots.

    For a quadratic equation Ax2+Bx+C=0Ax^2 + Bx + C = 0 to have equal roots, the discriminant must be zero.
    The discriminant is given by Δ=B2−4AC\Delta = B^2 - 4AC.

  2. Apply the condition to the given equation.

    The given quadratic equation is 2x2−6x+3a=02x^2 - 6x + 3a = 0.
    Comparing this to Ax2+Bx+C=0Ax^2 + Bx + C = 0, we have:
    A=2A = 2
    B=−6B = -6
    C=3aC = 3a

    Set the discriminant to zero:

    B2−4AC=0B^2 - 4AC = 0 (−6)2−4(2)(3a)=0(-6)^2 - 4(2)(3a) = 0
  3. Solve for aa.

    36−24a=036 - 24a = 0 36=24a36 = 24a a=3624a = \frac{36}{24} a=3×122×12a = \frac{3 \times 12}{2 \times 12} a=32a = \frac{3}{2}

    The value of aa for which the quadratic equation has equal roots is 32\frac{3}{2}.

    The correct option is D.

    D\boxed{\text{D}}
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