This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
100x + 80y = 694000
a) i) Form two equations to represent the above information.
Let be the cost of a bag of maize. Let be the cost of a bag of beans.
From Musamali's purchase: Musamali bought 100 bags of maize and 80 bags of beans for a total of Ksh 694,000.
From Cheruiyot's purchase: Cheruiyot bought bags of maize. Cheruiyot bought 50 bags of beans. Cheruiyot paid Ksh 116,500 less than Musamali. Amount paid by Cheruiyot = Ksh.
The two equations are:
a) ii) Find the cost of 1 bag of each item using the matrix method.
Step 1: Write the system of equations in matrix form.
Step 2: Find the determinant of the coefficient matrix .
Step 3: Find the inverse of the coefficient matrix .
Step 4: Multiply by the constant matrix to find .
Step 5: Calculate the values of and .
The cost of 1 bag of maize is Ksh 2500. The cost of 1 bag of beans is Ksh 5550.
b) In the subsequent month, the price of maize increased by 20% while that of beans reduced by 10%. Find the total amount he spent if he bought 40 bags of maize and 25 bags of beans.
Step 1: Calculate the new price of maize. New price of maize = Ksh.
Step 2: Calculate the new price of beans. New price of beans = Ksh.
Step 3: Calculate the total amount spent for the new purchase. Total amount spent = (40 bags of maize new maize price) + (25 bags of beans new beans price) Total amount spent = Total amount spent = Total amount spent = Ksh.
The total amount spent is .
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a) i) Form two equations to represent the above information. Let x be the cost of a bag of maize.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.