Here are the solutions for question 10:
a) What fraction remains after 6 months?
Step 1: Determine the fraction of the amount remaining each month.
Each month, half of the remaining amount is given away, so the fraction remaining is 21.
Step 2: Calculate the fraction remaining after 6 months.
After 6 months, the fraction remaining will be (21)6.
(21)6=2616=641
The fraction remaining after 6 months is 641.
b) What fraction remains after 12 months?
Step 1: Calculate the fraction remaining after 12 months.
After 12 months, the fraction remaining will be (21)12.
(21)12=212112=40961
The fraction remaining after 12 months is 40961.
c) Write each fraction as a power of 2 with a negative exponent.
Step 1: Express the fraction from part a) as a power of 2 with a negative exponent.
641=261=2−6
Step 2: Express the fraction from part b) as a power of 2 with a negative exponent.
40961=2121=2−12
The fractions as powers of 2 with negative exponents are 2−6 and 2−12.
d) What amount is remaining at the end of the year?
Step 1: Identify the initial amount and the fraction remaining at the end of the year.
The initial amount is \1,000,000.Theendoftheyearmeansafter12months.Frompartb),thefractionremainingis\frac{1}{4096}.
Step 2: Calculate the remaining amount.
$$ Remaining amount = \1,000,000 \times \frac{1}{4096} = \frac{$1,000,000}{4096} = $244.140625 Step3:Roundtheamounttotwodecimalplacesforcurrency. \approx $244.14 $$
The amount remaining at the end of the year is \boxed{\244.14}$.
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