This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
40
Here are the solutions to the problems:
4. Find the GCF of 40 and 120.
Step 1: Find the prime factorization of 40. Step 2: Find the prime factorization of 120. Step 3: Identify the common prime factors and their lowest powers. The common prime factors are 2 and 5. The lowest power of 2 is . The lowest power of 5 is . Step 4: Multiply the common prime factors with their lowest powers. Answer: The GCF of 40 and 120 is .
5. Write the decimal number 0.8333333... as a rational number.
Step 1: Let equal the decimal. Step 2: Multiply by 10 to move the non-repeating part to the left of the decimal. Step 3: Multiply by 100 to move one full repeating block to the left of the decimal. Step 4: Subtract equation (1) from equation (2) to eliminate the repeating part. Step 5: Solve for and simplify the fraction. Divide both the numerator and the denominator by their greatest common divisor, which is 15. Answer: The rational number is \boxed{\frac{5{6}}}.
6. Complete the equivalent fraction by filling in the box.
Step 1: Determine the factor by which the numerator 19 was multiplied to get 76. Step 2: Multiply the denominator 7 by the same factor. Answer: The completed equivalent fraction is .
7. Express 16/3 as a decimal correct to 4 decimal places.
Step 1: Divide 16 by 3. Step 2: Identify the first 5 decimal places to determine rounding. The fifth decimal place is 3. Step 3: Round to 4 decimal places. Since the fifth decimal place (3) is less than 5, we round down (keep the fourth decimal place as it is). Answer: as a decimal correct to 4 decimal places is .
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.