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Step-by-step solution

2 steps
  1. The given equation is 2b−9 m=3 m2b - 9\,\mathrm{m} = 3\,\mathrm{m}.

    Add 9 m9\,\mathrm{m} to both sides:

    2b−9 m+9 m=3 m+9 m2b - 9\,\mathrm{m} + 9\,\mathrm{m} = 3\,\mathrm{m} + 9\,\mathrm{m} 2b=12 m2b = 12\,\mathrm{m}

    Divide both sides by 2:

    b=12 m2b = \frac{12\,\mathrm{m}}{2} b=6 mb = 6\,\mathrm{m}

    b = 6,m

    b = 6 m

  2. The given equation is 3m=17 m3m = 17\,\mathrm{m}.

    Divide both sides by 3:

    m=17 m3m = \frac{17\,\mathrm{m}}{3} m≈5.67 mm \approx 5.67\,\mathrm{m}

    \boxed{m \approx 5.67,\

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