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Given GEH = 35^ and EG = 25.4 cm.

Mathematics

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Answer

52.1 cm\text{52.1 cm}

Step-by-step solution

6 steps

Here are the steps to calculate the length of EFEF:

  1. Calculate the lengths of EHEH and GHGH in the right-angled triangle △GEH\triangle GEH.

    Given ∠GEH=35∘\angle GEH = 35^\circ and EG=25.4EG = 25.4 cm.

    EH=EGcos⁡(35∘)=25.4cos⁡(35∘)EH = EG \cos(35^\circ) = 25.4 \cos(35^\circ) GH=EGsin⁡(35∘)=25.4sin⁡(35∘)GH = EG \sin(35^\circ) = 25.4 \sin(35^\circ)
  2. Calculate ∠EGH\angle EGH.

    In △GEH\triangle GEH, the sum of angles is 180∘180^\circ. Since ∠GHE=90∘\angle GHE = 90^\circ:

    ∠EGH=180∘−90∘−35∘=55∘\angle EGH = 180^\circ - 90^\circ - 35^\circ = 55^\circ
  3. Calculate ∠HGF\angle HGF.

    Given ∠EGF=120∘\angle EGF = 120^\circ. We know ∠EGF=∠EGH+∠HGF\angle EGF = \angle EGH + \angle HGF.

    ∠HGF=∠EGF−∠EGH=120∘−55∘=65∘\angle HGF = \angle EGF - \angle EGH = 120^\circ - 55^\circ = 65^\circ
  4. Calculate the length of HFHF in the right-angled triangle △GHF\triangle GHF.

    We use the value of GHGH from Step 1 and ∠HGF\angle HGF from Step 3.

    HF=GHtan⁡(∠HGF)=(25.4sin⁡(35∘))tan⁡(65∘)HF = GH \tan(\angle HGF) = (25.4 \sin(35^\circ)) \tan(65^\circ)
  5. Calculate the total length of EFEF.

    EF=EH+HFEF = EH + HF EF=25.4cos⁡(35∘)+(25.4sin⁡(35∘))tan⁡(65∘)EF = 25.4 \cos(35^\circ) + (25.4 \sin(35^\circ)) \tan(65^\circ) EF≈25.4(0.81915)+(25.4(0.57358))(2.14451)EF \approx 25.4(0.81915) + (25.4(0.57358)) (2.14451) EF≈20.80641+(14.57893)(2.14451)EF \approx 20.80641 + (14.57893) (2.14451) EF≈20.80641+31.26850EF \approx 20.80641 + 31.26850 EF≈52.07491 cmEF \approx 52.07491 \text{ cm}
  6. Round the answer to three significant figures.

    EF≈52.1 cmEF \approx \boxed{\text{52.1 cm}}
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