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Given P = 4 & 3 1 & 2 , then P2 = P x P.

Mathematics

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Answer

(191867)\begin{pmatrix} 19 & 18 \\ 6 & 7 \end{pmatrix}

Step-by-step solution

3 steps

Here's the solution for question 5 b) i):

To calculate P2P^2, we multiply matrix PP by itself.

  1. Write out the matrix multiplication.

    Given P=(4312)P = \begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix}, then P2=P×PP^2 = P \times P.

    P2=(4312)(4312)P^2 = \begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} 4 & 3 \\ 1 & 2 \end{pmatrix}
  2. Perform the matrix multiplication.

    Multiply rows of the first matrix by columns of the second matrix.
    For the element in the first row, first column: (4×4)+(3×1)=16+3=19(4 \times 4) + (3 \times 1) = 16 + 3 = 19
    For the element in the first row, second column: (4×3)+(3×2)=12+6=18(4 \times 3) + (3 \times 2) = 12 + 6 = 18
    For the element in the second row, first column: (1×4)+(2×1)=4+2=6(1 \times 4) + (2 \times 1) = 4 + 2 = 6
    For the element in the second row, second column: (1×3)+(2×2)=3+4=7(1 \times 3) + (2 \times 2) = 3 + 4 = 7

  3. Form the resulting matrix P2P^2.

    P2=(191867)P^2 = \begin{pmatrix} 19 & 18 \\ 6 & 7 \end{pmatrix}

    The calculated value of P2P^2 is (191867)\boxed{\begin{pmatrix} 19 & 18 \\ 6 & 7 \end{pmatrix}}.

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