Given that (2x+3)/(x2 − 3x + 2) = (A)/(x-1) + (B)/(x-2), find the values of A and B.

Here are the solutions to questions 9, 10, and 11.

Question 9:
Given that $\frac{2x+3}{x^2 - 3x + 2} = \frac{A}{x-1} + \frac{B}{x-2}$, find the values of A and B.

Step 1: Factor the denominator on the left side.
The quadratic expression $x^2 - 3x + 2$ can be factored as $(x-1)(x-2)$.
So the equation becomes:

$$\frac{2x+3}{(x-1)(x-2)} = \frac{A}{x-1} + \frac{B}{x-2}$$

Step