Given that (4x - 1), (2x + 5) and (5x + 11) are consecutive terms of an Arithmetic Progression (A. P.). Find the values of x.

In an Arithmetic Progression, the difference between any two consecutive terms is constant. If $a$, $b$, and $c$ are consecutive terms of an A.P., then $b - a = c - b$.

Given the consecutive terms are $(4x - 1)$, $(2x + 5)$, and $(5x + 11)$.
Let $a = 4x - 1$, $b = 2x + 5$, and $c = 5x + 11$.
So, we can write the equation:

For the left side:

For the right side:

Now the equation is:

Subtract $3x$ from both sides:

Subtract 6 from both sides:

Divide by -5: