h) Solve for x in:
i) 27x=93x−2
Step 1: Express both bases as powers of the same number, 3.
(33)x=(32)3x−2
Step 2: Apply the power rule (am)n=amn.
33x=32(3x−2)
33x=36x−4
Step 3: Equate the exponents since the bases are the same.
3x=6x−4
Step 4: Solve for x.
3x−6x=−4
−3x=−4
x=−3−4
x=34
The solution for h) i) is $\boxed{x =