This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Eyi ni bi a ṣe le wa HCF (Highest Common Factor) fun nọmba kọọkan: 1) HCF ti 24 ati 36 Step 1: Wa awọn nọmba akọkọ ti 24 ati 36. 24 = 2 × 2 × 2 × 3 = 2^3 × 3^1 36 = 2 × 2 × 3 × 3 = 2^2 × 3^2 Step 2: Wa awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. Awọn nọmba akọkọ ti o wọpọ ni 2 ati 3. Agbara ti o kere julọ fun 2 jẹ 2^2 ati fun 3 jẹ 3^1. Step 3: Ṣe isodipupo awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. HCF = 2^2 × 3^1 = 4 × 3 = 12 Idahun: 12 2) HCF ti 40 ati 60 Step 1: Wa awọn nọmba akọkọ ti 40 ati 60. 40 = 2 × 2 × 2 × 5 = 2^3 × 5^1 60 = 2 × 2 × 3 × 5 = 2^2 × 3^1 × 5^1 Step 2: Wa awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. Awọn nọmba akọkọ ti o wọpọ ni 2 ati 5. Agbara ti o kere julọ fun 2 jẹ 2^2 ati fun 5 jẹ 5^1. Step 3: Ṣe isodipupo awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. HCF = 2^2 × 5^1 = 4 × 5 = 20 Idahun: 20 3) HCF ti 54, 72 ati 90 Step 1: Wa awọn nọmba akọkọ ti 54, 72 ati 90. 54 = 2 × 3 × 3 × 3 = 2^1 × 3^3 72 = 2 × 2 × 2 × 3 × 3 = 2^3 × 3^2 90 = 2 × 3 × 3 × 5 = 2^1 × 3^2 × 5^1 Step 2: Wa awọn nọmba akọkọ ti o wọpọ si gbogbo awọn nọmba pẹlu agbara ti o kere julọ. Awọn nọmba akọkọ ti o wọpọ ni 2 ati 3. Agbara ti o kere julọ fun 2 jẹ 2^1 ati fun 3 jẹ 3^2. Step 3: Ṣe isodipupo awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. HCF = 2^1 × 3^2 = 2 × 9 = 18 Idahun: 18 4) HCF ti 432 ati 72 Step 1: Wa awọn nọmba akọkọ ti 432 ati 72. 432 = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 2^4 × 3^3 72 = 2 × 2 × 2 × 3 × 3 = 2^3 × 3^2 Step 2: Wa awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. Awọn nọmba akọkọ ti o wọpọ ni 2 ati 3. Agbara ti o kere julọ fun 2 jẹ 2^3 ati fun 3 jẹ 3^2. Step 3: Ṣe isodipupo awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. HCF = 2^3 × 3^2 = 8 × 9 = 72 Idahun: 72 5) HCF ti 14, 21 ati 28 Step 1: Wa awọn nọmba akọkọ ti 14, 21 ati 28. 14 = 2 × 7 = 2^1 × 7^1 21 = 3 × 7 = 3^1 × 7^1 28 = 2 × 2 × 7 = 2^2 × 7^1 Step 2: Wa awọn nọmba akọkọ ti o wọpọ si gbogbo awọn nọmba pẹlu agbara ti o kere julọ. Nọmba akọkọ ti o wọpọ ni 7. Agbara ti o kere julọ fun 7 jẹ 7^1. Step 3: Ṣe isodipupo awọn nọmba akọkọ ti o wọpọ pẹlu agbara ti o kere julọ. HCF = 7^1 = 7 Idahun: 7 3 done, 2 left today. You're making progress.