Here u wrote p(x= 0) = 1/16 but it should be 0/16

Mathematics

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You're pointing out a specific part of the calculation. Let's clarify.

The probability P(X=0)P(X=0) represents the probability of getting zero heads when tossing four fair coins.
There is only one way to get zero heads: TTTT (Tail, Tail, Tail, Tail).
Since there are 24=162^4 = 16 total possible outcomes when tossing four coins, the probability of getting zero heads is 116\frac{1}{16}.

So, P(X=0)=116P(X=0) = \frac{1}{16} is correct.

The term 0(116)0 \left(\frac{1}{16}\right) in the expectation calculation E[X]=∑xP(X=x)E[X] = \sum x P(X=x) is the contribution of x=0x=0 to the sum. This term simplifies to 0, but it uses the correct probability P(X=0)=116P(X=0) = \frac{1}{16}.

If P(X=0)P(X=0) were 0/160/16, it would mean it's impossible to get zero heads, which is not true for four coin tosses.

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