Identify the digit in the first decimal place, which is 0.

Here are the solutions to the problems: 1. (a) Express 6.093 to one decimal place. Step 1: Identify the digit in the first decimal place, which is 0. Step 2: Look at the digit immediately to its right, which is 9. Step 3: Since 9 5, round up the digit in the first decimal place. 6.093 ≈ 6.1 1. (b) Evaluate (3)/(4) + (1)/(2) - (1)/(3). Step 1: Find a common denominator for 4, 2, and 3. The least common multiple (LCM) is 12. Step 2: Convert each fraction to have a denominator of 12. (3)/(4) = (3 × 3)/(4 × 3) = (9)/(12) (1)/(2) = (1 × 6)/(2 × 6) = (6)/(12) (1)/(3) = (1 × 4)/(3 × 4) = (4)/(12) Step 3: Perform the addition and subtraction. (9)/(12) + (6)/(12) - (4)/(12) = (9 + 6 - 4)/(12) = (15 - 4)/(12) = (11)/(12) 2. Given the sets A = \1, 2, 3, 4, 5, 6, 7, 8, 9, 10\ and B = \2, 3, 6, 7\. 2. (a) Find A'. Assuming that A is the universal set for this context, the complement of A (A') would be the set of elements in the universal set that are not in A. A' = A A = 2. (b) Find A B. A B represents the intersection of sets A and B, which includes all elements common to both sets. A = \1, 2, 3, 4, 5, 6, 7, 8, 9, 10\ B = \2, 3, 6, 7\ The elements common to both sets are 2, 3, 6, 7. A B = \2, 3, 6, 7\ 2. (c) Find n(B). n(B) represents the number of elements in set B. B = \2, 3, 6, 7\ There are 4 elements in set B. n(B) = 4 3. Complete the truth table below. Step 1: Fill the P column by negating the truth values of P. Step 2: Fill the P Q column by applying the OR operator to the values in the P column and the Q column. The OR operator is true if at least one of its operands is true. | P | Q | P | P Q | |---|---|----------|-----------------| | T | T | F | T | | T | F | F | F | | F | T | T | T | | F | F | T | T | That's 2 down. 3 left today — send the next one.