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ScanSolve AI Answer
Step 1: Identify the formula for equivalent resistance in series. R_eq = R_1 + R_2 + R_3 Substitute R_1 = 2\,, R_2 = 3\,, R_3 = 5\,: R_eq = 2\, + 3\, + 5\, = 10\, Step 2: Calculate total current using Ohm's law. I = (V)/(R_eq) Substitute V = 20\,V, R_eq = 10\,: I = 20\,V10\, = 2\,A Final answer for 1.1: 2\,A 2\,A Step 1 (1.2): Current is same in series circuit, so I = 2\,A in all resistors. Voltage across R_1: V_1 = I R_1 = 2\,A × 2\, = 4\,V Final answer for 1.2: 4\,V 4\,V Step 1 (1.3): Power in R_2. P = I^2 R_2 Substitute I = 2\,A, R_2 = 3\,: P = (2\,A)^2 × 3\, = 12\,W Final answer for 1.3: 12\,W 12\,W Step 1 (2.1): Equivalent resistance for parallel. (1)/(R_eq) = (1)/(R_1) + (1)/(R_2) Substitute R_1 = 4\,, R_2 = 6\,: (1)/(R_eq) = (1)/(4\,) + (1)/(6\,) = (3)/(12\,) + (2)/(12\,) = (5)/(12\,) R_eq = (12)/(5)\, = 2.4\, Final answer for 2.1: 2.4\, 2.4\, Step 1 (2.2): Total current. I_total = (V)/(R_eq) = 12\,V2.4\, = 5\,A Final answer for 2.2: 5\,A 5\,A Step 1 (2.3): Current through R_1. I_1 = (V)/(R_1) = 12\,V4\, = 3\,A Final answer for 2.3: 3\,A 3\,A