On receiving the mark-sheet from the university (a) I realised (b) that I had got only passing marks in English. (c) / No Error (d)

Step 1: Identify the passing marks required.

Marks obtained = 332 marks
Marks short = 4 marks
Passing marks required = marks obtained + marks short
$332 + 4 = 336$ marks

Step 2: Passing percentage formula.

Passing percentage = 40% = $\frac{40}{100} = 0.4$
Passing marks = $0.4 \times$ maximum marks (M marks)

Step 3: Set up the equation.

$0.4 M = 336$ marks

Step 4: Solve for maximum marks M.

$M = \frac{336}{0.4}$ marks
$M = 336 \times \frac{10}{4}$ marks
$336 \div 4 = 84$
$84 \times 10 = 840$ marks

Maximum marks = 840 marks