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If T = 2π sqrt(L/G), make G the subject of the formula. Hence, find the value of G to the nearest whole number when T = 45, L = 8 and π = 3.142.

Mathematics

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Step-by-step solution

5 steps

To make GG the subject of the formula and then find its value, we follow these steps:

  1. Rearrange the formula to make GG the subject.

    The given formula is:

    T=2πLGT = 2\pi \sqrt{\frac{L}{G}}

    Divide both sides by 2π2\pi:

    T2π=LG\frac{T}{2\pi} = \sqrt{\frac{L}{G}}

    Square both sides to eliminate the square root:

    (T2π)2=LG\left(\frac{T}{2\pi}\right)^2 = \frac{L}{G} T24π2=LG\frac{T^2}{4\pi^2} = \frac{L}{G}

    To isolate GG, we can cross-multiply or take the reciprocal of both sides and then multiply by LL:

    GT2=4π2LG T^2 = 4\pi^2 L

    Divide by T2T^2:

    G=4π2LT2G = \frac{4\pi^2 L}{T^2}
  2. Substitute the given values into the rearranged formula.

    Given values are T=45T=45, L=8L=8, and π=3.142\pi=3.142.

    G=4×(3.142)2×8(45)2G = \frac{4 \times (3.142)^2 \times 8}{(45)^2}
  3. Calculate the squares of π\pi and TT.

    (3.142)2=9.872164(3.142)^2 = 9.872164 (45)2=2025(45)^2 = 2025
  4. Substitute these values back into the equation for GG and calculate.

    G=4×9.872164×82025G = \frac{4 \times 9.872164 \times 8}{2025} G=315.9092482025G = \frac{315.909248}{2025} G≈0.1560045669G \approx 0.1560045669
  5. Round the value of GG to the nearest whole number.

    G≈0G \approx \boxed{0}
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