In a certain country it is known that 34% of the adult population has some knowledge of a foreign language, If 6 adults from this country are chosen at random, find the probability that at least one of those chosen will have some knowledge of a foreign language.

The variable $X$ represents the number of attempts to the first success, with the probability of success $p = 0.8$ for each attempt. This means $X$ follows a Geometric distribution with parameter $p = 0.8$.

For a Geometric distribution $X \sim Geo(p)$:
The mean is $E(X) = \frac{1}{p}$.
The variance is $Var(X) = \frac{1-p}{p^2}$.

Substitute $p = 0.8$:

Given $Y = 3X + 2$.
Using the properties of expectation $E(aX + b) = aE(X) + b$:

Using the properties of variance $Var(aX + b) = a^2Var(X)$:

The mean of Y is $\boxed{5.75}$ and the variance of Y is $\boxed{2.8125}$.