Solve in nepali

Mathematics

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Answer

2

Step-by-step solution

4 steps
  1. दिइएको समीकरण लेख्नुहोस्।

    हामीलाई दिइएको समीकरण छ:

    x+1x=2x + \frac{1}{x} = 2
  2. समीकरणको दुवै पक्षलाई वर्ग गर्नुहोस्।

    (x+1x)2=(2)2\left(x + \frac{1}{x}\right)^2 = (2)^2
  3. बायाँ पक्षलाई (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2 सूत्र प्रयोग गरी विस्तार गर्नुहोस्।

    x2+2⋅x⋅1x+(1x)2=4x^2 + 2 \cdot x \cdot \frac{1}{x} + \left(\frac{1}{x}\right)^2 = 4 x2+2+1x2=4x^2 + 2 + \frac{1}{x^2} = 4
  4. x2+1x2x^2 + \frac{1}{x^2} को मान पत्ता लगाउनुहोस्।

    समीकरणको दुवै पक्षबाट २ घटाउनुहोस्:

    x2+1x2=4−2x^2 + \frac{1}{x^2} = 4 - 2 x2+1x2=2x^2 + \frac{1}{x^2} = 2

    अतः, x2+1x2x^2 + \frac{1}{x^2} को मान 2\boxed{2} हो।

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