Increase £1.45 by £1.65. 2. What is the cost of 25 cm at £1.20 per metre? 3. This clock is 20 min fast. Write the correct time in digits. Use a.m. or p.m. 4. Find the total cost of two toy cars each c

Here are the solutions to the problems. 1. Increase 1.45 by 1.65. Step 1: Add the two amounts together. 1.45 + 1.65 = 3.10 The increased amount is 3.10. 2. What is the cost of 25 cm at 1.20 per metre? Step 1: Convert 25 cm to meters. There are 100 cm in 1 m. 25 cm = (25)/(100) m = 0.25 m Step 2: Calculate the cost. Multiply the length in meters by the cost per meter. 0.25 m × 1.20/m = 0.30 The cost is 0.30. 3. This clock is 20 min fast. Write the correct time in digits. Use a.m. or p.m. Step 1: Read the time shown on the clock. The hour hand is between 7 and 8. The minute hand is pointing at 3, which represents 15 minutes past the hour. Since it says "morning", the time shown is 7:15 a.m. Step 2: Subtract 20 minutes from the displayed time to find the correct time. 7:15 a.m. - 20 minutes Subtracting 15 minutes brings it to 7:00 a.m. Subtracting another 5 minutes (20 - 15 = 5) brings it to 6:55 a.m. The correct time is 6:55 a.m.. 4. Find the total cost of two toy cars each costing 1.38. Step 1: Multiply the cost of one toy car by 2. 2 × 1.38 = 2.76 The total cost is 2.76. 5. How much less than a whole one is the smallest of these fractions? (1)/(2), (1)/(7), (1)/(4), (1)/(10), (1)/(3) Step 1: Identify the smallest fraction. For unit fractions (fractions with a numerator of 1), the fraction with the largest denominator is the smallest. Comparing the denominators (2, 7, 4, 10, 3), the largest denominator is 10. Therefore, the smallest fraction is (1)/(10). Step 2: Calculate how much less than a whole one (which is 1) the smallest fraction is. 1 - (1)/(10) = (10)/(10) - (1)/(10) = (9)/(10) The smallest fraction is (9)/(10) less than a whole one. Last free one today — make it count tomorrow, or type /upgrade for unlimited.