We read your photo as:

Solve the indicial equation 2 (2x+1)=27(x−1)

Mathematics

ScanSolve AI Answer

Step-by-step solution

5 steps

Here's how to solve the indicial equation:

The equation given is 3(2x+1)=27(x−1)3(2x+1) = 27(x-1).

  1. Expand both sides of the equation.

    3(2x)+3(1)=27(x)−27(1)3(2x) + 3(1) = 27(x) - 27(1) 6x+3=27x−276x + 3 = 27x - 27
  2. Group the terms with xx on one side and the constant terms on the other side.

    Subtract 27x27x from both sides:

    6x−27x+3=−276x - 27x + 3 = -27

    Subtract 3 from both sides:

    6x−27x=−27−36x - 27x = -27 - 3
  3. Simplify both sides of the equation.

    −21x=−30-21x = -30
  4. Solve for xx by dividing both sides by −21-21.

    x=−30−21x = \frac{-30}{-21} x=3021x = \frac{30}{21}
  5. Simplify the fraction and provide the decimal approximation.

    Divide both the numerator and the denominator by their greatest common divisor, which is 3:

    x=30÷321÷3x = \frac{30 \div 3}{21 \div 3} x=107x = \frac{10}{7}

    As a decimal, rounded to four decimal places:

    x≈1.4286x \approx 1.4286

    The solution to the equation is ∗x=107≈1.4286\boxed*{x = \frac{10}{7} \approx 1.4286}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp