Step 1: Simplify the integral expression.
The given function is f(x)=∫x23x4−4x3−x2+1d(2x).
First, rewrite d(2x) as 2dx.
f(x)=∫x23x4−4x3−x2+1(2dx)
Factor out the constant 2:
f(x)=2∫x23x4−4x3−x2+1dx
Divide each term in the numerator by x2:
f(x)=2∫(x23x4−x24x3−x2x2+x21)dx
f(x)=2∫(3x2−4x−1+x−2)dx
Step 2: Perform the integration.
Integrate each term:
f(x)=2(2+13x2+1−1+14x1+1−0+1x0+1+−2+1x−2+1)+C
f(x)=2(33x3−24x2−x−1x−1)+C
f(x)=2(x3−2x2−x−x1)+C
Distribute the 2:
f(x)=2x3−4x2−2x−x2+C
Step 3: Use the condition f(1)=2 to find the constant C.
Substitute x=1 into the expression for f(x):
f(1)=2(1)3−4(1)2−2(1)−12+C
2=2(1)−4(1)−2−2+C
2=2−4−2−2+C
2=−6+C
Solve for C:
C=2+6
C=8
Step 4: Write the complete function f(x).
Substitute the value of C back into the function:
f(x)=2x3−4x2−2x−x2+8
Step 5: Calculate f(−1).
Substitute x=−1 into the function:
f(−1)=2(−1)3−4(−1)2−2(−1)−−12+8
f(−1)=2(−1)−4(1)−(−2)−(−2)+8
f(−1)=−2−4+2+2+8
f(−1)=−6+4+8
f(−1)=−2+8
f(−1)=6
The final answer is 6.
Send me the next one 📸