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Interchange two numbers to make the equation correct: 18 × 3 ÷ 9 + 5 − 6 = 2

Mathematics

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Answer

3\text{3}

To make the given equation correct, we need to interchange two numbers.
The original equation is:

18×3÷9+5−6=218 \times 3 \div 9 + 5 - 6 = 2

First, let's evaluate the Left Hand Side (LHS) of the original equation:

18×3÷9+5−618 \times 3 \div 9 + 5 - 6 =54÷9+5−6= 54 \div 9 + 5 - 6 =6+5−6= 6 + 5 - 6 =11−6= 11 - 6 =5= 5

Since 5≠25 \neq 2, the original equation is incorrect. We need to find which interchange makes it correct.

Let's test each option:

  • Option 1: Interchange 18 and 6 The equation becomes:

    6×3÷9+5−18=26 \times 3 \div 9 + 5 - 18 = 2

    Evaluate LHS:

    6×3÷9+5−186 \times 3 \div 9 + 5 - 18 =18÷9+5−18= 18 \div 9 + 5 - 18 =2+5−18= 2 + 5 - 18 =7−18= 7 - 18 =−11= -11

    Since −11≠2-11 \neq 2, this option is incorrect.

  • Option 2: Interchange 3 and 5 The equation becomes:

    18×5÷9+3−6=218 \times 5 \div 9 + 3 - 6 = 2

    Evaluate LHS:

    18×5÷9+3−618 \times 5 \div 9 + 3 - 6 =90÷9+3−6= 90 \div 9 + 3 - 6 =10+3−6= 10 + 3 - 6 =13−6= 13 - 6 =7= 7

    Since 7≠27 \neq 2, this option is incorrect.

  • Option 3: Interchange 2 and 3 This means we replace '3' on the left side with '2', and '2' (the result on the right side) with '3'. The equation becomes:

    18×2÷9+5−6=318 \times 2 \div 9 + 5 - 6 = 3

    Evaluate LHS:

    18×2÷9+5−618 \times 2 \div 9 + 5 - 6 =36÷9+5−6= 36 \div 9 + 5 - 6 =4+5−6= 4 + 5 - 6 =9−6= 9 - 6 =3= 3

    Since 3=33 = 3, this equation is correct. This option works.

  • Option 4: Interchange 5 and 9 The equation becomes:

    18×3÷5+9−6=218 \times 3 \div 5 + 9 - 6 = 2

    Evaluate LHS:

    18×3÷5+9−618 \times 3 \div 5 + 9 - 6 =54÷5+9−6= 54 \div 5 + 9 - 6 =10.8+9−6= 10.8 + 9 - 6 =19.8−6= 19.8 - 6 =13.8= 13.8

    Since 13.8≠213.8 \neq 2, this option is incorrect.

Therefore, interchanging 2 and 3 makes the equation correct.

The final answer is 3\text{3}

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