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Japuka eneo la umbo lililo hapo juu.

Mathematics

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Hapa kuna hatua za kutafuta eneo la kila umbo:

Umbo la Kwanza (Chini):
Umbo hili linaweza kugawanywa katika mstatili tatu.

  1. Tafuta eneo la mstatili wa kwanza (chini).

    Urefu = 8 sm8 \text{ sm}, Upana = 2 sm2 \text{ sm}.

    Eneo1=urefu×upana=8 sm×2 sm=16 sm2\text{Eneo}_1 = \text{urefu} \times \text{upana} = 8 \text{ sm} \times 2 \text{ sm} = 16 \text{ sm}^2
  2. Tafuta eneo la mstatili wa pili (katikati).

    Urefu = 6 sm6 \text{ sm}, Upana = 2 sm2 \text{ sm}.

    Eneo2=urefu×upana=6 sm×2 sm=12 sm2\text{Eneo}_2 = \text{urefu} \times \text{upana} = 6 \text{ sm} \times 2 \text{ sm} = 12 \text{ sm}^2
  3. Tafuta eneo la mstatili wa tatu (juu).

    Urefu = 4 sm4 \text{ sm}, Upana = 2 sm2 \text{ sm}.

    Eneo3=urefu×upana=4 sm×2 sm=8 sm2\text{Eneo}_3 = \text{urefu} \times \text{upana} = 4 \text{ sm} \times 2 \text{ sm} = 8 \text{ sm}^2
  4. Jumlisha maeneo yote kupata eneo kamili la umbo.

    Eneo Jumla=Eneo1+Eneo2+Eneo3=16 sm2+12 sm2+8 sm2=36 sm2\text{Eneo Jumla} = \text{Eneo}_1 + \text{Eneo}_2 + \text{Eneo}_3 = 16 \text{ sm}^2 + 12 \text{ sm}^2 + 8 \text{ sm}^2 = 36 \text{ sm}^2

    Eneo kamili la umbo la kwanza ni 36 sm2\boxed{\text{36 sm}^2}.

    Umbo la Pili (Katikati):
    Umbo hili linaweza kugawanywa katika mraba mmoja wa katikati na mstatili nne zinazouzunguka.

  5. Tafuta eneo la mraba wa katikati.

    Urefu = 5 sm5 \text{ sm}, Upana = 5 sm5 \text{ sm}.

    Eneomraba=urefu×upana=5 sm×5 sm=25 sm2\text{Eneo}_{\text{mraba}} = \text{urefu} \times \text{upana} = 5 \text{ sm} \times 5 \text{ sm} = 25 \text{ sm}^2
  6. Tafuta eneo la mstatili mmoja wa pembeni.

    Urefu = 5 sm5 \text{ sm}, Upana = 2 sm2 \text{ sm}.

    Eneomstatili mmoja=urefu×upana=5 sm×2 sm=10 sm2\text{Eneo}_{\text{mstatili mmoja}} = \text{urefu} \times \text{upana} = 5 \text{ sm} \times 2 \text{ sm} = 10 \text{ sm}^2
  7. Tafuta eneo la mstatili zote nne za pembeni.

    Kuna mstatili nne, hivyo:

    Eneomstatili nne=4×10 sm2=40 sm2\text{Eneo}_{\text{mstatili nne}} = 4 \times 10 \text{ sm}^2 = 40 \text{ sm}^2
  8. Jumlisha eneo la mraba na eneo la mstatili zote nne.

    Eneo Jumla=Eneomraba+Eneomstatili nne=25 sm2+40 sm2=65 sm2\text{Eneo Jumla} = \text{Eneo}_{\text{mraba}} + \text{Eneo}_{\text{mstatili nne}} = 25 \text{ sm}^2 + 40 \text{ sm}^2 = 65 \text{ sm}^2

    Eneo kamili la umbo la pili ni 65 sm2\boxed{\text{65 sm}^2}.

    Umbo la Tatu (Juu):
    Umbo hili lina pembetatu na nusu duara.

  9. Tafuta eneo la pembetatu.

    Msingi = 10 sm10 \text{ sm}, Kimo = 9 sm9 \text{ sm}.

    Eneopembetatu=12×msingi×kimo=12×10 sm×9 sm=45 sm2\text{Eneo}_{\text{pembetatu}} = \frac{1}{2} \times \text{msingi} \times \text{kimo} = \frac{1}{2} \times 10 \text{ sm} \times 9 \text{ sm} = 45 \text{ sm}^2
  10. Tafuta eneo la nusu duara.

    Kipenyo = 10 sm10 \text{ sm}, hivyo rediasi r=10 sm2=5 smr = \frac{10 \text{ sm}}{2} = 5 \text{ sm}.

    Eneonusu duara=12×π×r2=12×π×(5 sm)2=12×π×25 sm2=12.5π sm2\text{Eneo}_{\text{nusu duara}} = \frac{1}{2} \times \pi \times r^2 = \frac{1}{2} \times \pi \times (5 \text{ sm})^2 = \frac{1}{2} \times \pi \times 25 \text{ sm}^2 = 12.5 \pi \text{ sm}^2

    Kutumia π≈3.14159\pi \approx 3.14159:

    12.5π sm2≈12.5×3.14159 sm2≈39.27 sm212.5 \pi \text{ sm}^2 \approx 12.5 \times 3.14159 \text{ sm}^2 \approx 39.27 \text{ sm}^2
  11. Jumlisha eneo la pembetatu na eneo la nusu duara.

    Eneo Jumla=Eneopembetatu+Eneonusu duara=45 sm2+12.5π sm2\text{Eneo Jumla} = \text{Eneo}_{\text{pembetatu}} + \text{Eneo}_{\text{nusu duara}} = 45 \text{ sm}^2 + 12.5 \pi \text{ sm}^2 Eneo Jumla≈45 sm2+39.27 sm2=84.27 sm2\text{Eneo Jumla} \approx 45 \text{ sm}^2 + 39.27 \text{ sm}^2 = 84.27 \text{ sm}^2

    Eneo kamili la umbo la tatu ni 45+12.5π sm2≈84.27 sm2\boxed{\text{45} + 12.5\pi \text{ sm}^2 \approx 84.27 \text{ sm}^2}.

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