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Jitin had 8 green apples and 6 red apples. He exchanged 2 green ones for red ones. How many of each has he now?

Mathematics

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Answer

6 green apples and 8 red apples\text{6 green apples and 8 red apples}

Step-by-step solution

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here's the solution to the problem:

1. Jitin had 8 green apples and 6 red apples. He exchanged 2 green ones for red ones. How many of each has he now?

  1. Identify the initial number of apples.

    Jitin started with 8 green apples and 6 red apples.

  2. Calculate the number of green apples after the exchange.

    He exchanged 2 green apples, meaning he gave them away.

    New green apples=Initial green apples−2\text{New green apples} = \text{Initial green apples} - 2 New green apples=8−2=6\text{New green apples} = 8 - 2 = 6
  3. Calculate the number of red apples after the exchange.

    He received 2 red apples in exchange for the green ones.

    New red apples=Initial red apples+2\text{New red apples} = \text{Initial red apples} + 2 New red apples=6+2=8\text{New red apples} = 6 + 2 = 8
  4. State the final number of each type of apple.

    Jitin now has 6 green apples and 8 red apples.

    The final answer is 6 green apples and 8 red apples\text{6 green apples and 8 red apples}.

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