Kwanini ukirusha jiwe juu linarudi chini

Mathematics

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Mvuto wa Dunia

Jibu: Jiwe linarudi chini kwa sababu ya mvuto wa Dunia.

Step 1: Unapokirusha jiwe juu, lina kasi ya awali ya juu, v0v_0 (kwa mfano, v0=20m/sv_0 = 20 \, \mathrm{m/s}).

Step 2: Mvuto unatoa加 kuongeza kasi thabiti ya chini, g=9.8m/s2g = 9.8 \, \mathrm{m/s^2}.

a=g=9.8m/s2a = -g = -9.8 \, m/s^2

Step 3: Kasi ya jiwe hupungua kwa wakati:

v=v0+at=v0gtv = v_0 + a t = v_0 - g t

Step 4: Kwenye urefu wa juu zaidi, v=0v = 0:

0=v0gtmax0 = v_0 - g t_{\max}

tmax=v0gt_{\max} = \frac{v_0}{g}

Kwa v0=20m/sv_0 = 20 \, \mathrm{m/s}: tmax=209.82.04st_{\max} = \frac{20}{9.8} \approx 2.04 \, \mathrm{s}.

Step 5: Na kuendelea, vv inakuwa hasi (chini), jiwe linaanza kushuka.

Step 6: Nafasi ya jiwe (kutoka mahali pa kurusha):

y(t)=v0t12gt2y(t) = v_0 t - \frac{1}{2} g t^2

Hii ni parabola inayofikia ymaxy_{\max} wakati tmaxt_{\max}, kisha inarudi y=0y=0.

ymax=v0(v0g)12g(v0g)2=v022g40019.620.4my_{\max} = v_0 \left( \frac{v_0}{g} \right) - \frac{1}{2} g \left( \frac{v_0}{g} \right)^2 = \frac{v_0^2}{2g} \approx \frac{400}{19.6} \approx 20.4 \, m

Kwa hivyo, mvuto unasisitiza kila wakati chini, hivyo jiwe linapunguza kasi juu, kisha linarudi chini kwa kasi sawa (bila upinzani wa hewa).

Mvuto wa Dunia

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