This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
Kwanini ukirusha jiwe juu linarudi chini
Mathematics
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Answer
Mvuto wa Dunia
Jibu: Jiwe linarudi chini kwa sababu ya mvuto wa Dunia.
Step 1: Unapokirusha jiwe juu, lina kasi ya awali ya juu, (kwa mfano, ).
Step 2: Mvuto unatoa加 kuongeza kasi thabiti ya chini, .
Step 3: Kasi ya jiwe hupungua kwa wakati:
Step 4: Kwenye urefu wa juu zaidi, :
Kwa : .
Step 5: Na kuendelea, inakuwa hasi (chini), jiwe linaanza kushuka.
Step 6: Nafasi ya jiwe (kutoka mahali pa kurusha):
Hii ni parabola inayofikia wakati , kisha inarudi .
Kwa hivyo, mvuto unasisitiza kila wakati chini, hivyo jiwe linapunguza kasi juu, kisha linarudi chini kwa kasi sawa (bila upinzani wa hewa).
Mvuto wa Dunia
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ScanSolve AI Answer
Jibu: Jiwe linarudi chini kwa sababu ya mvuto wa Dunia. Step 1: Unapokirusha jiwe juu, lina kasi ya awali ya juu, v_0 (kwa mfano, v_0 = 20 \, m/s). Step 2: Mvuto unatoa加 kuongeza kasi thabiti ya chini, g = 9.8 \, m/s^2. a = -g = -9.8 \, m/s^2 Step 3: Kasi ya jiwe hupungua kwa wakati: v = v_0 + a t = v_0 - g t Step 4: Kwenye urefu wa juu zaidi, v = 0: 0 = v_0 - g t_ t_ = (v_0)/(g) Kwa v_0 = 20 \, m/s: t_ = (20)/(9.8) ≈ 2.04 \, s. Step 5: Na kuendelea, v inakuwa hasi (chini), jiwe linaanza kushuka. Step 6: Nafasi ya jiwe (kutoka mahali pa kurusha): y(t) = v_0 t - (1)/(2) g t^2 Hii ni parabola inayofikia y_ wakati t_, kisha inarudi y=0. y_ = v_0 ( (v_0)/(g) ) - (1)/(2) g ( (v_0)/(g) )^2 = (v_0^2)/(2g) ≈ (400)/(19.6) ≈ 20.4 \, m Kwa hivyo, mvuto unasisitiza kila wakati chini, hivyo jiwe linapunguza kasi juu, kisha linarudi chini kwa kasi sawa (bila upinzani wa hewa). Mvuto wa Dunia