Kwanini ukirusha jiwe juu linarudi chini

$$0 = v_0 - g t_{\max}$$ $$t_{\max} = \frac{v_0}{g}$$

Kwa $v_0 = 20 \, \mathrm{m/s}$: $t_{\max} = \frac{20}{9.8} \approx 2.04 \, \mathrm{s}$.

$$y(t) = v_0 t - \frac{1}{2} g t^2$$

Hii ni parabola inayofikia $y_{\max}$ wakati $t_{\max}$, kisha inarudi $y=0$.

$$y_{\max} = v_0 \left( \frac{v_0}{g} \right) - \frac{1}{2} g \left( \frac{v_0}{g} \right)^2 = \frac{v_0^2}{2g} \approx \frac{400}{19.6} \approx 20.4 \, \mathrm{m}$$

Kwa hivyo, mvuto unasisitiza kila wakati chini, hivyo jiwe linapunguza kasi juu, kisha linarudi chini kwa kasi sawa (bila upinzani wa hewa).

Mvuto wa Dunia