Lebelela molawana Dirisa molawana go batla dipalo tse di tlogetsweng. Janaan dira tse. Agela go 20 ka mekgwa e 3 e farologaneng. Kgwetlho Akanyafela Dirisa dipalo 1, 2, 3, 4, le 5. Dipalo tse 3 mo moleng o mongwe le o mongwe di tlhakanne go fa 10. Molawana: Dirisa palo nngwe le nngwe gangwe fela.

I'll complete the explanation for the challenge puzzle.

Challenge Puzzle:

• Analysis: Let the numbers in the boxes be $T$ (top), $L$ (left), $C$ (center), $R$ (right), $B$ (bottom). The numbers to use are 1, 2, 3, 4, 5, each exactly once. The sum of the numbers in each line must be 10. The arrows indicate four lines:

  1. Vertical: $T + C + B = 10$
  2. Horizontal: $L + C + R = 10$
  3. Diagonal 1 (Top-Right): $T + C + R = 10$
  4. Diagonal 2 (Left-Bottom): $L + C + B = 10$

• Step 1: Compare the line equations. From line 1 ($T + C + B = 10$) and line 3 ($T + C + R = 10$), we can deduce:

  $$T + C + B = T + C + R$$

  Subtracting $T+C$ from both sides gives:

  $$B = R$$

  This means the number in the bottom box must be the same as the number in the right box.

• Step 2: Check against the rule. The rule states: "Dirisa palo nngwe le nngwe gangwe fela." (Use each number once only.) If $B$ and $R$ must be the same number, but the puzzle requires using each of the numbers 1, 2, 3, 4, 5 exactly once, this creates a direct contradiction. It is impossible to place a unique set of five numbers into five boxes if two of those boxes must contain the same number.

• Conclusion: Based on the given rules and the visual representation of the lines, this challenge puzzle is impossible to solve as stated.