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Make V the subject, C = my + v / v

Mathematics

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Answer

M=16M = 16

V=myC−1V = \frac{my}{C - 1}

Step-by-step solution

6 steps

Here are the solutions to your assignment questions.

1) Make M the subject of M=4\sqrt{M} = 4

  1. To isolate MM, square both sides of the equation.

    (M)2=42(\sqrt{M})^{2} = 4^{2}
  2. Simplify both sides.

    M=16M = 16

    The subject is MM.

    M=16\boxed{M = 16}

    2) Make V the subject of C=my+VVC = \frac{my + V}{V}

  3. Multiply both sides by VV to remove the denominator.

    C⋅V=my+VV⋅VC \cdot V = \frac{my + V}{V} \cdot V CV=my+VCV = my + V
  4. Gather all terms containing VV on one side of the equation.

    Subtract VV from both sides.

    CV−V=myCV - V = my
  5. Factor out VV from the terms on the left side.

    V(C−1)=myV(C - 1) = my
  6. Divide both sides by (C−1)(C - 1) to isolate VV.

    V=myC−1V = \frac{my}{C - 1}

    The subject is VV.

    V=myC−1\boxed{V = \frac{my}{C - 1}}
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