This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Nimeona picha tena. Tayari tumeshughulikia maswali 1, 2, na 3a. Sasa tutaendelea na sehemu inayofuata ya swali la 3, ambayo inahusisha habari iliyobaki. Ingawa haijaandikwa wazi kama 'b)', tutatumia taarifa iliyobaki kukokotoa jumla ya mchele uliyonunuliwa. 3. A school bought some rice to be used for 6 days. On the first day, the school used (1)/(6) of the rice. On the second day, (1)/(5) of the remaining rice was used. The rest of the rice was shared equally for the remaining days. The school used 37.5 kg of rice on each of the remaining days. b) Jumla ya mchele uliyonunuliwa na shule. Step 1: Tambua idadi ya siku zilizobaki. Jumla ya siku ni 6. Siku 2 zimetumika (siku ya kwanza na ya pili). Siku zilizobaki = 6 - 2 = 4 siku. Step 2: Kokotoa jumla ya mchele uliotumika kwa siku 4 zilizobaki. Shule ilitumia 37.5 kg ya mchele kwa kila moja ya siku 4 zilizobaki. Jumla ya mchele kwa siku 4 zilizobaki = 4 × 37.5 kg = 150 kg. Step 3: Tumia sehemu ya mchele iliyobaki (kutoka sehemu 'a') kupata jumla ya mchele uliyonunuliwa. Kutoka sehemu 'a', tuligundua kuwa (2)/(3) ya mchele ndiyo iliyobaki na kugawanywa kwa siku zilizobaki. Hivyo, 150 kg inawakilisha (2)/(3) ya jumla ya mchele uliyonunuliwa. Acha T iwe jumla ya mchele uliyonunuliwa. (2)/(3) T = 150 kg Step 4: Tatua kwa T. Ili kupata T, tunazidisha pande zote mbili kwa (3)/(2): T = 150 kg × (3)/(2) T = (150 ÷ 2) × 3 kg T = 75 × 3 kg T = 225 kg Jumla ya mchele uliyonunuliwa na shule ni 225 kg. The final answer is 225 kg. That's 2 down. 3 left today — send the next one.