Study the map extract provided on a scale of 1:50,000 and answer the questions that follow. In your new outline, insert and name: (i) the secondary road, (ii) the trigonometrical station, (iii) Mayo Jarandi settlement, (iv) River Juji and indicate its direction of flow with an arrow.

Step 1: Calculate the mass of cold water. m_c = 25~mL × 1~gmL = 25~g Step 2: Calculate the mass of hot water. m_h = 50~mL × 1~gmL = 50~g Step 3: Set up the heat balance equation (heat lost by hot water equals heat gained by cold water). m_h c (T_h - T_f) = m_c c (T_f - T_c) where c = 1~calg · ^, T_h = 80^, T_c = 20^. Step 4: Substitute the known values (c cancels out). 50~g (80^ - T_f) = 25~g (T_f - 20^) Step 5: Expand both sides. 4000~cal - 50 T_f = 25 T_f - 500~cal Step 6: Add 50 T_f to both sides. 4000~cal + 500~cal = 25 T_f + 50 T_f 4500~cal = 75 T_f Step 7: Solve for T_f. T_f = 4500~cal75 = 60^ Step 8: Calculate heat lost by hot water. Q_h = m_h c (T_h - T_f) = 50~g × 1~calg · ^ × (80^ - 60^) Q_h = 50~g × 20^ = 1000~cal Step 9: Calculate heat gained by cold water. Q_c = m_c c (T_f - T_c) = 25~g × 1~calg · ^ × (60^ - 20^) Q_c = 25~g × 40^ = 1000~cal Final temperature of the mixture: 60^ Heat lost by hot water: 1000~cal Heat gained by cold water: 1000~cal