Find the mean score to the nearest whole number. Then, find the mean of the remaining distribution if the largest value of 34 is deleted from a set of 30 observations with a mean of 15.

Welcome back Abiodun😍😍😍 — been a while! Let's pick up where you left off. Here are the solutions to the problems: Problem 1: Find the mean score to the nearest whole number. Step 1: Calculate the sum of frequencies ( f) and the sum of (mark × frequency) ( fx). The given data is: Marks (x): 4, 5, 6, 7, 8, 9 Frequency (f): 5, 8, 5, 6, 4, 2 f = 5 + 8 + 5 + 6 + 4 + 2 = 30 fx = (4 × 5) + (5 × 8) + (6 × 5) + (7 × 6) + (8 × 4) + (9 × 2) fx = 20 + 40 + 30 + 42 + 32 + 18 = 182 Step 2: Calculate the mean using the formula Mean = ( fx)/( f). Mean = (182)/(30) = 6.066... Step 3: Round the mean to the nearest whole number. Mean ≈ 6 The mean score to the nearest whole number is 6. Problem 2: The mean of 30 observations recorded in an experiment is 15. If the observation with the largest value of 34 is deleted, find the mean of the remaining distribution. Step 1: Calculate the total sum of the original 30 observations. Given: Number of observations (N_1) = 30, Mean (x_1) = 15. The sum of observations ( x_1) is given by x_1 = x_1 × N_1. x_1 = 15 × 30 = 450 Step 2: Calculate the new sum of observations after deleting the value 34. The observation with value 34 is deleted. New sum of observations ( x_2) = x_1 - 34 = 450 - 34 = 416 Step 3: Calculate the new number of observations. After deleting one observation, the new number of observations (N_2) is: N_2 = 30 - 1 = 29 Step 4: Calculate the mean of the remaining distribution. The new mean (x_2) is given by x_2 = ( x_2)/(N_2). x_2 = (416)/(29) ≈ 14.3448 The mean of the remaining distribution is 14.34. Send me the next one 📸