This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
92.31%~\ce{C},~7.69%~\ce{H}
Step 1: Molecular formula of benzene is .
Step 2: Mass of carbon in benzene.
Step 3: Percentage of carbon.
First, simplify fraction:
Then,
Step 4: Percentage of hydrogen.
Step 5: Reason for sooty flame.
Benzene has high carbon content (). Oxygen is insufficient for complete combustion to and , so unburnt carbon forms soot (black smoke).
92.31%~\ce{C,~7.69%~\ce{H}}
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Molecular formula of benzene is C_6H_6. M = 6 × 12 + 6 × 1 = 72 + 6 = 78~g/mol Step 2: Mass of carbon in benzene.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.