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Mathematics

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Here are the solutions to the multiplication problems. The pattern used is that the bottom-right number (BR) is the product of the top-left (TL), top-right (TR), and bottom-left (BL) numbers: BR=TL×TR×BL\text{BR} = \text{TL} \times \text{TR} \times \text{BL}.

1)
Given: TL=3, TR=2, BL=9. Find BR.

  1. Multiply the top-left, top-right, and bottom-left numbers.

    3×2×93 \times 2 \times 9
  2. Perform the multiplication.

    3×2×9=6×9=543 \times 2 \times 9 = 6 \times 9 = 54

    The missing number is 54\boxed{\text{54}}.
    (Note: The student's written answer of 84 does not fit this pattern.)

    2)
    Given: TL=2, TR=5, BL=2. Find BR.

  3. Multiply the top-left, top-right, and bottom-left numbers.

    2×5×22 \times 5 \times 2
  4. Perform the multiplication.

    2×5×2=10×2=202 \times 5 \times 2 = 10 \times 2 = 20

    The missing number is 20\boxed{\text{20}}.

    3)
    Given: TL=8, TR=3, BL=4. Find BR.

  5. Multiply the top-left, top-right, and bottom-left numbers.

    8×3×48 \times 3 \times 4
  6. Perform the multiplication.

    8×3×4=24×4=968 \times 3 \times 4 = 24 \times 4 = 96

    The missing number is 96\boxed{\text{96}}.

    4)
    Given: TL=7, TR=3, BL=5. Find BR.

  7. Multiply the top-left, top-right, and bottom-left numbers.

    7×3×57 \times 3 \times 5
  8. Perform the multiplication.

    7×3×5=21×5=1057 \times 3 \times 5 = 21 \times 5 = 105

    The missing number is 105\boxed{\text{105}}.

    5)
    Given: TL=2, BL=3, BR=24. Find TR.

  9. Set up the equation based on the pattern

    TL×TR×BL=BR\text{TL} \times \text{TR} \times \text{BL} = \text{BR}.

    2×TR×3=242 \times \text{TR} \times 3 = 24
  10. Simplify the left side and solve for TR.

    6×TR=246 \times \text{TR} = 24 TR=246=4\text{TR} = \frac{24}{6} = 4

    The missing number is 4\boxed{\text{4}}.

    6)
    Given: TL=5, TR=5, BL=2. Find BR.

  11. Multiply the top-left, top-right, and bottom-left numbers.

    5×5×25 \times 5 \times 2
  12. Perform the multiplication.

    5×5×2=25×2=505 \times 5 \times 2 = 25 \times 2 = 50

    The missing number is 50\boxed{\text{50}}.

    7)
    Given: TR=6, BL=2, BR=36. Find TL.

  13. Set up the equation based on the pattern

    TL×TR×BL=BR\text{TL} \times \text{TR} \times \text{BL} = \text{BR}.

    TL×6×2=36\text{TL} \times 6 \times 2 = 36
  14. Simplify the left side and solve for TL.

    TL×12=36\text{TL} \times 12 = 36 TL=3612=3\text{TL} = \frac{36}{12} = 3

    The missing number is 3\boxed{\text{3}}.

    8)
    Given: TL=4, TR=5, BR=400. Find BL.

  15. Set up the equation based on the pattern

    TL×TR×BL=BR\text{TL} \times \text{TR} \times \text{BL} = \text{BR}.

    4×5×BL=4004 \times 5 \times \text{BL} = 400
  16. Simplify the left side and solve for BL.

    20×BL=40020 \times \text{BL} = 400 BL=40020=20\text{BL} = \frac{400}{20} = 20

    The missing number is 20\boxed{\text{20}}.

    9)
    Given: TL=2, TR=5, BL=2. Find BR.

  17. Multiply the top-left, top-right, and bottom-left numbers.

    2×5×22 \times 5 \times 2
  18. Perform the multiplication.

    2×5×2=10×2=202 \times 5 \times 2 = 10 \times 2 = 20

    The missing number is 20\boxed{\text{20}}.
    (Note: This problem is identical to . The student's written answer of 5 does not fit this pattern.)

    10)
    Given: TL=6, BL=2, BR=60. Find TR.

  19. Set up the equation based on the pattern

    TL×TR×BL=BR\text{TL} \times \text{TR} \times \text{BL} = \text{BR}.

    6×TR×2=606 \times \text{TR} \times 2 = 60
  20. Simplify the left side and solve for TR.

    12×TR=6012 \times \text{TR} = 60 TR=6012=5\text{TR} = \frac{60}{12} = 5

    The missing number is 5\boxed{\text{5}}.

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