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Home > Mathematics Homework Help > Solution

Solve number 9-11

Asked on March 28, 2026|Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on March 28, 2026
Step 1: Solve Question 9. Given the sets: $A = \{1, 2, 3\}$ $B = \{2, 3, 4\}$ $C = \{3, 4, 5\}$ Compute the number of elements in $A \cup B \cup C$, denoted as $|A \cup B \cup C|$. First, find the union of all three sets: $$A \cup B = \{1, 2, 3\} \cup \{2, 3, 4\} = \{1, 2, 3, 4\}$$ $$(A \cup B) \cup C = \{1, 2, 3, 4\} \cup \{3, 4, 5\}$$ $$A \cup B \cup C = \{1, 2, 3, 4, 5\}$$ Now, count the number of elements in the resulting set: $$|A \cup B \cup C| = 5$$ The answer for Question 9 is: $\boxed{5}$ Step 2: Solve Question 10. Given: Number of students enrolled in mathematics ($|M|$) = 100 Number of students enrolled in science ($|S|$) = 120 Number of students enrolled in both subjects ($|M \cap S|$) = 80 Find the number of students enrolled in at least one of the subjects, which is $|M \cup S|$. Use the Principle of Inclusion-Exclusion for two sets: $$|M \cup S| = |M| + |S| - |M \cap S|$$ Substitute the given values: $$|M \cup S| = 100 + 120 - 80$$ $$|M \cup S| = 220 - 80$$ $$|M \cup S| = 140$$ The answer for Question 10 is: $\boxed{140}$ Step 3: Solve Question 11. Given the sets: $A = \{1, 2\}$ $B = \{2, 3\}$ $C = \{3, 4\}$ a) Compute $(A \cup B) \cup C$ First, calculate $A \cup B$: $$A \cup B = \{1, 2\} \cup \{2, 3\} = \{1, 2, 3\}$$ Next, find the union of this result with $C$: $$(A \cup B) \cup C = \{1, 2, 3\} \cup \{3, 4\}$$ $$(A \cup B) \cup C = \{1, 2, 3, 4\}$$ b) Compute $A \cup (B \cup C)$ First, calculate $B \cup C$: $$B \cup C = \{2, 3\} \cup \{3, 4\} = \{2, 3, 4\}$$ Next, find the union of $A$ with this result: $$A \cup (B \cup C) = \{1, 2\} \cup \{2, 3, 4\}$$ $$A \cup (B \cup C) = \{1, 2, 3, 4\}$$ The answers for Question 11 are: *a) $\boxed{\{1, 2, 3, 4\}}$ *b) $\boxed{\{1, 2, 3, 4\}}$

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Home›Mathematics Homework Help›Solve number 9-11
Q

Solve number 9-11

March 28, 2026|Mathematics
Solve number 9-11

Solve number 9-11

ScanSolve AI

ScanSolve AI Answer

Answered on March 28, 2026

Step 1: Solve Question 9. Given the sets: A={1,2,3}A = \{1, 2, 3\}A={1,2,3} B={2,3,4}B = \{2, 3, 4\}B={2,3,4} C={3,4,5}C = \{3, 4, 5\}C={3,4,5} Compute the number of elements in A∪B∪CA \cup B \cup CA∪B∪C, denoted as ∣A∪B∪C∣|A \cup B \cup C|∣A∪B∪C∣.

First, find the union of all three sets: A∪B={1,2,3}∪{2,3,4}={1,2,3,4}A \cup B = \{1, 2, 3\} \cup \{2, 3, 4\} = \{1, 2, 3, 4\}A∪B={1,2,3}∪{2,3,4}={1,2,3,4} (A∪B)∪C={1,2,3,4}∪{3,4,5}(A \cup B) \cup C = \{1, 2, 3, 4\} \cup \{3, 4, 5\}(A∪B)∪C={1,2,3,4}∪{3,4,5} A∪B∪C={1,2,3,4,5}A \cup B \cup C = \{1, 2, 3, 4, 5\}A∪B∪C={1,2,3,4,5} Now, count the number of elements in the resulting set: ∣A∪B∪C∣=5|A \cup B \cup C| = 5∣A∪B∪C∣=5 The answer for Question 9 is: 5\boxed{5}5​

Step 2: Solve Question 10. Given: Number of students enrolled in mathematics (∣M∣|M|∣M∣) = 100 Number of students enrolled in science (∣S∣|S|∣S∣) = 120 Number of students enrolled in both subjects (∣M∩S∣|M \cap S|∣M∩S∣) = 80 Find the number of students enrolled in at least one of the subjects, which is ∣M∪S∣|M \cup S|∣M∪S∣.

Use the Principle of Inclusion-Exclusion for two sets: ∣M∪S∣=∣M∣+∣S∣−∣M∩S∣|M \cup S| = |M| + |S| - |M \cap S|∣M∪S∣=∣M∣+∣S∣−∣M∩S∣ Substitute the given values: ∣M∪S∣=100+120−80|M \cup S| = 100 + 120 - 80∣M∪S∣=100+120−80 ∣M∪S∣=220−80|M \cup S| = 220 - 80∣M∪S∣=220−80 ∣M∪S∣=140|M \cup S| = 140∣M∪S∣=140 The answer for Question 10 is: 140\boxed{140}140​

Step 3: Solve Question 11. Given the sets: A={1,2}A = \{1, 2\}A={1,2} B={2,3}B = \{2, 3\}B={2,3} C={3,4}C = \{3, 4\}C={3,4}

a) Compute (A∪B)∪C(A \cup B) \cup C(A∪B)∪C First, calculate A∪BA \cup BA∪B: A∪B={1,2}∪{2,3}={1,2,3}A \cup B = \{1, 2\} \cup \{2, 3\} = \{1, 2, 3\}A∪B={1,2}∪{2,3}={1,2,3} Next, find the union of this result with CCC: (A∪B)∪C={1,2,3}∪{3,4}(A \cup B) \cup C = \{1, 2, 3\} \cup \{3, 4\}(A∪B)∪C={1,2,3}∪{3,4} (A∪B)∪C={1,2,3,4}(A \cup B) \cup C = \{1, 2, 3, 4\}(A∪B)∪C={1,2,3,4} b) Compute A∪(B∪C)A \cup (B \cup C)A∪(B∪C) First, calculate B∪CB \cup CB∪C: B∪C={2,3}∪{3,4}={2,3,4}B \cup C = \{2, 3\} \cup \{3, 4\} = \{2, 3, 4\}B∪C={2,3}∪{3,4}={2,3,4} Next, find the union of AAA with this result: A∪(B∪C)={1,2}∪{2,3,4}A \cup (B \cup C) = \{1, 2\} \cup \{2, 3, 4\}A∪(B∪C)={1,2}∪{2,3,4} A∪(B∪C)={1,2,3,4}A \cup (B \cup C) = \{1, 2, 3, 4\}A∪(B∪C)={1,2,3,4} The answers for Question 11 are: *a) {1,2,3,4}\boxed{\{1, 2, 3, 4\}}{1,2,3,4}​ *b) {1,2,3,4}\boxed{\{1, 2, 3, 4\}}{1,2,3,4}​

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