Step 1: Solve Question 9.
Given the sets:
A={1,2,3}
B={2,3,4}
C={3,4,5}
Compute the number of elements in A∪B∪C, denoted as ∣A∪B∪C∣.
First, find the union of all three sets:
A∪B={1,2,3}∪{2,3,4}={1,2,3,4}
(A∪B)∪C={1,2,3,4}∪{3,4,5}
A∪B∪C={1,2,3,4,5}
Now, count the number of elements in the resulting set:
∣A∪B∪C∣=5
The answer for Question 9 is:
5
Step 2: Solve Question 10.
Given:
Number of students enrolled in mathematics (∣M∣) = 100
Number of students enrolled in science (∣S∣) = 120
Number of students enrolled in both subjects (∣M∩S∣) = 80
Find the number of students enrolled in at least one of the subjects, which is ∣M∪S∣.
Use the Principle of Inclusion-Exclusion for two sets:
∣M∪S∣=∣M∣+∣S∣−∣M∩S∣
Substitute the given values:
∣M∪S∣=100+120−80
∣M∪S∣=220−80
∣M∪S∣=140
The answer for Question 10 is:
140
Step 3: Solve Question 11.
Given the sets:
A={1,2}
B={2,3}
C={3,4}
a) Compute (A∪B)∪C
First, calculate A∪B:
A∪B={1,2}∪{2,3}={1,2,3}
Next, find the union of this result with C:
(A∪B)∪C={1,2,3}∪{3,4}
(A∪B)∪C={1,2,3,4}
b) Compute A∪(B∪C)
First, calculate B∪C:
B∪C={2,3}∪{3,4}={2,3,4}
Next, find the union of A with this result:
A∪(B∪C)={1,2}∪{2,3,4}
A∪(B∪C)={1,2,3,4}
The answers for Question 11 are:
*a) {1,2,3,4}
*b) {1,2,3,4}