O is the center of the circle. ADO = 37^. OCD = 45^. EC is tangent to circle at C. ABCD is cyclic quad. EC = 7, DE = 5. Calculate CDE?

Here's the continuation of the solution for the geometry problem.

Given Information:

• O is the center of the circle.
• $\angle ADO = 37^\circ$.
• $\angle OCD = 45^\circ$. (Assuming $\angle LCD$ in the text is a typo for $\angle OCD$ based on the diagram).
• EC is a tangent to the circle at C.
• ABCD is a cyclic quadrilateral.
• EC = 7 cm, DE = 5 cm.

---

Part a) i) Calculate $\angle CDE$, giving reasons.

Step 1: Find $\angle ODC$.
In $\triangle ODC$, OC = OD (radii of the same circle